Timeline for How to calculate the delta-v necessary for a suborbital "transfer" of ice from Mars' pole to equator?
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 12, 2018 at 13:18 | vote | accept | uhoh | ||
| Jun 12, 2018 at 13:18 | answer | added | uhoh | timeline score: 1 | |
| Jun 12, 2018 at 6:01 | comment | added | uhoh | @JCRM not necessary, just interested in the calculation which produces the initial delta-v. Assume a single impulse. At the linked comment, there was speculation that the value is 3 to 4 km/s, let's find out. | |
| Jun 12, 2018 at 5:30 | comment | added | user20636 | Do you want to soft land it? | |
| Jun 12, 2018 at 3:30 | answer | added | Paul | timeline score: 2 | |
| Jun 11, 2018 at 20:51 | history | tweeted | twitter.com/StackSpaceExp/status/1006277686187167745 | ||
| Jun 11, 2018 at 17:23 | comment | added | uhoh | @Jack Thanks for that, but it's not really a complete answer to this question. "...the vis viva equation can be used to get Δv...". I didn't ask for the name of the equation, I'm really looking for the complete solution as well as the numerical value. If you can start with that equation and insert the other assumptions and get it all to work, then that would be a great answer! | |
| Jun 11, 2018 at 17:15 | comment | added | Jack | Looks like this question is very similar has has a fairly thorough answer. Should be straightforward to replace values for the moon with Mars's | |
| Jun 11, 2018 at 17:02 | answer | added | SF. | timeline score: 4 | |
| Jun 11, 2018 at 16:52 | comment | added | uhoh | @Uwe I usually calculate elliptical orbits based on periapsis and apoapsis, or semi-major axis and eccentricity. I've never done it assuming intercept points with the surface, that's an ICBM, not really "like another elliptical orbit". So instead of saying it's the same, can you post an answer showing how it's done, because it's a different problem than what I've done before. | |
| Jun 11, 2018 at 16:50 | history | edited | uhoh | CC BY-SA 4.0 |
edited title
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| Jun 11, 2018 at 16:40 | comment | added | Uwe | If you neglect the atmosphere and assume a point mass for the planet, this trajectory should be calculated just like another elliptical orbit. Parts of this orbit may be below the surface, but the part from pole to equator should be above. | |
| Jun 11, 2018 at 16:18 | history | asked | uhoh | CC BY-SA 4.0 |