Timeline for What does "m Δv" stand for in the rocket equation?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Jun 21, 2021 at 8:52 | vote | accept | Cliff Miles | ||
| Jun 20, 2021 at 17:29 | comment | added | Greg | The analysis starts with the conservation of momentum. That being worked out, presumably what you really want is velocity versus time, so you need to isolate the v term. At that point it's just math. Formally you're "separating the variables". You pretty much always want to do that. It doesn't make any sense to integrate dm on the right side if m is sitting there on the left, because m is not a constant, and the reason it's not a constant is because of the dm. | |
| Jun 20, 2021 at 14:28 | comment | added | Cliff Miles | Oh, so does that mean that in my explanation (since I'm doing a project on this), I won't have to explain that stage, just simply divide by M, integrate, and be done with it? ALSO, what exactly would we be achieving by dividing the equation by M before integrating? | |
| Jun 20, 2021 at 11:25 | history | answered | SE - stop firing the good guys | CC BY-SA 4.0 |