Timeline for What is the terminal velocity of the Falcon 9 at sea level (on Earth)?
Current License: CC BY-SA 4.0
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| Sep 17 at 8:48 | comment | added | Peter - Reinstate Monica | @ErinAnne Yes, of course. This answer was not meant to produce a robust number but to "plug" plausible values into the relevant formula (which, I think, nobody had done so far here) to show how one would in principle go about it. The resulting number is within the expected order of magnitude which I found encouraging. | |
| Sep 17 at 1:05 | comment | added | Erin Anne | "The projected surface area of the landing legs is just a wild guess" :( this answer could be off by quite a lot from both A and C being rough guesses. | |
| Sep 16 at 23:23 | history | edited | Peter - Reinstate Monica | CC BY-SA 4.0 |
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| Sep 16 at 23:21 | comment | added | Peter - Reinstate Monica | @Mark I meant to state that, got lost in the editing -- the "effective" area (which I only guesstimate based on pictures) when I consider fins and legs is meant to take the different coefficient into account. For the booster cylinder without legs it's also not perfect because the front end is not smooth. | |
| Sep 16 at 22:15 | comment | added | Mark | You can't use the "long cylinder" drag coefficient for the landing legs. They're probably somewhere between "flat plate" (1.17) and "open hemisphere" (0.38). There's also the issue of turbulent flow around various components, which greatly increases the drag. | |
| Sep 16 at 4:26 | history | edited | Peter - Reinstate Monica | CC BY-SA 4.0 |
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| Sep 16 at 4:09 | history | edited | Peter - Reinstate Monica | CC BY-SA 4.0 |
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| Sep 16 at 3:53 | history | answered | Peter - Reinstate Monica | CC BY-SA 4.0 |