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Jul 12, 2015 at 19:40 history tweeted twitter.com/#!/StackSpaceExp/status/620316862308614144
Jul 11, 2015 at 16:09 vote accept Zoran
Jul 11, 2015 at 15:52 answer added Mark Adler timeline score: 7
Jul 11, 2015 at 14:26 history edited kim holder
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Jul 11, 2015 at 12:36 comment added user Also, the beam width isn't a binary on/off either, but a gradual reduction of signal strength. You pick a value, say, -30 dB to peak power, and calculate the specific antenna's beam width at the specific intended frequency to that power ratio, then state that as the transmission beam width. If you are slightly outside of that, you might receive at -32 dB to peak power, whereas if you are slightly inside of it, the value might be -28 dB.
Jul 11, 2015 at 12:32 history edited user CC BY-SA 3.0
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Jul 11, 2015 at 12:28 comment added user The emission beamwidth is also a specific angle (dependent on the relationship between antenna size and transmission frequency or wavelength). For large antennas and high frequencies (upper UHF and higher, which is what the DSN uses) this can quite easily become fractions of a degree, but over tens of AU, that's still quite a lot of margin. You'll want to maintain as good a lock as possible to maximize the useful signal strength received, but it's not a total disaster if you are slightly off: the mission's radio link budget is going to have to include some margin for error and variance anyway.
Jul 11, 2015 at 8:50 comment added Hobbes Related question (about the antenna position of the receiver on Earth): space.stackexchange.com/questions/9803/…
Jul 11, 2015 at 7:33 review First posts
Jul 11, 2015 at 7:40
Jul 11, 2015 at 7:29 history asked Zoran CC BY-SA 3.0