9
$\begingroup$

If a coronal mass ejection with the intensity of the Carrington event1 or more hit Mars, what would happen to an astronaut on its surface who is too far from their base to return to in time? Assuming they have travelled too far in a Mars roving vehicle, and the solar flare hits now, would they survive, or for a limited time? Would the flare knock out the Mars roving vehicle's power unit? Mars has a thin atmosphere and weak magnetic fields.

As for the base, I'm assuming it is underground so that a solar flare wouldn't have much impact there.

1The Carrington Event was a powerful geomagnetic storm on September 1–2, 1859, during solar cycle 10 (1855–1867). A solar coronal mass ejection (CME) hit Earth's magnetosphere and induced the largest geomagnetic storm on record. The associated "white light flare" in the solar photosphere was observed and recorded by British astronomers Richard Carrington and Richard Hodgson. The storm caused strong auroral displays and wrought havoc with telegraph systems. The now-standard unique IAU identifier for this flare is SOL1859-09-01

$\endgroup$
6
  • 1
    $\begingroup$ This is going to be impossible to answer without making assumptions about the degree of protection given to both the astronaut and the vehicle. If you have some boundaries in mind for those assumptions then it wouldn't be a bad idea to say (e.g. no better protection than apollo landings) though thereafter the astronaut response side of the problem is in medical expertise territory. $\endgroup$
    – Puffin
    Commented Apr 16, 2021 at 11:43
  • $\begingroup$ @Puffin Yes, let's assume the astronauts use the same spacesuits used by the Apollo 15, 16 and 17 moonstriders, just less massive so that they weigh the same in Mars' higher gravity. As for the vehicle, let's assume it is enclosed, pressurized maybe. Similar to the ones in the movie "Moon", in case you ever watched it. And we can also assume the astronauts were trained for incidents like this. $\endgroup$
    – Giovanni
    Commented Apr 16, 2021 at 12:54
  • 2
    $\begingroup$ The areal density of Earth's atmosphere is about 1000 g/cm^2, so if we take Mars to be 1% it will be 10 g/cm^2 which according to this table can stop very roughly 30 MeV protons. The atmosphere is much much thicker than the wall of a spacecraft on its way to Mars. We don't have a proton energy spectrum from the Carrington event, so this will require proton energy information from more recent CME's. $\endgroup$
    – uhoh
    Commented Apr 16, 2021 at 21:21
  • 2
    $\begingroup$ It's worth noting that there is almost always a warning before a CME occurs, and they take quite a few days to reach Earth, and more to reach Mars (CMEs don't travel at light speed). Only the gamma rays travel at light speed. In other words, before all the particles from the CME come raining down on Mars, there will be enough time for the astronauts to reach their base. This is assuming Solar Activity is monitored of course which it most definitely will be when humans do eventually go to Mars. $\endgroup$
    – Star Man
    Commented Apr 16, 2021 at 23:58
  • $\begingroup$ @StarMan Would the astronauts on the ISS have to be returned to Earth if such CME was to come? $\endgroup$
    – Giovanni
    Commented Apr 17, 2021 at 5:23

3 Answers 3

6
$\begingroup$

There is a detailed review of space weather effects on humans in space by Townsend [2021]. They highlight several solar energetic particle (SEP) events that would have exceeded 30 day short-term organ damage limits from recent observations, all of which are likely to be weaker than the Carrington event. They also provide the dose limits for blood forming organs (BFOs), the heart, skin, eyes, and the central nervous system (CNS) for 30 days, 1 year, and career to give the reader a baseline reference. All these values fall in the 250--1500 mGy-Eq (milliGray-Equivalent) range for 30 days. Most of the exposure estimates for recent SEP events like that on July 14, 2000 are >1000 mGy, i.e., you'd exceed a 30 day dosage limit in a matter of a few minutes.

They examine a huge event in 775 AD that would would have caused radiation sickness and/or death in both men and women even with 40 g cm-2 of aluminum shielding (typical values used are ~5-10 g cm-2).

Update
For reference, hematopoietic syndrome (bone marrow syndrome) starts with mild symptoms at ~0.3 Gy (Gy = Gray = J/kg = mean energy imparted/deposited per unit mass) and severe symptoms occur around 0.7 Gy. Gastrointestinal syndrome begins around 6 Gy and is severe around 10 Gy. Cardiovascular/central nervous system syndrome (the most severe) begins around 20 Gy and shows full expression above 50 Gy.

Mars is only ~50% further from the Sun than Earth. The radial dependence of SEP peak intensity depends on magnetic field line connection to the source, but typically falls as $r^{-3}$ [e.g., see Lario et al., 2013]. So the peak intensity at Mars would be up to 70% weaker than that seen at Earth.

My original answer was mostly written to emphasize that while one may get some protection from the Martian atmosphere and remnant magnetic fields, this does not account for the ~6-9 month trip from Earth to Mars where the astronauts would have very little, if any, protection from particles with energies >10 MeV.

So if I am understanding the results found at https://agupubs.onlinelibrary.wiley.com/doi/full/10.1029/2018SW001921 correctly, even with 30 g $cm^{-2}$ of aluminum shielding one would accumulate more than 1 mGy/day (number jumps to >100 mGy/day at 1 g $cm^{-2}$ of aluminum shielding). If we assume the lowest travel time of ~6 months (~180 days), then the accumulated dose could exceed 0.18 Gy (18 Gy) from Earth to Mars. Granted, this assumes an SEP event every day so the actual value is likely lower.

The event simulated in this paper occurred on September 10-14, 2017. It was a decent event, but not an extreme event by any means. The paper says "...one of the strongest SEP events in recent years..." which is fully accurate as there have been very few SEP events at all since the start of solar minimum in 2006-2008, i.e., this has been a very weak solar cycle. For comparison, the peak intensity of the >1 MeV protons in the September 2017 event was recorded at a few x $10^{4} \ cm^{-2} s^{-1} sr^{-1}$. The peak fluxes of ~1 MeV protons for the Bastille Eay event (i.e., July 2000) exceeded 1000 $cm^{-2} s^{-1} sr^{-1} MeV^{-1}$ or in the units of the September 2017 paper $\sim10^{9} \ cm^{-2} s^{-1} sr^{-1}$ [e.g., Tylka et al., 2001]. That is, the Bastille Eay event proton fluxes were upwards of 5 orders of magnitude larger. So even if we account for the $r^{-3}$ to Mars, a drop of 70% will not reduce 5 orders of magnitude down to the September 2017 event.

This is all based on a worst case scenario, which must be planned for because as shown above for the Bastille Eay event, one event could literally end the mission before the astronauts even arive at Mars. Further, the Bastille Eay event generated ground level enhancements (GLEs), i.e., the event was so strong that charged particles (and neutrons) made it to the Earth's surface! That is, they penetrated past both Earth's magnetic field and its atmosphere. Mars' atmosphere is roughly ~1% of the volume of Earth's atmosphere. Earth's magnetic field exceeds 65,000 nT in places while Mars' peaks out around 1500 nT, i.e., Earth's is over 40 times stronger.

The above reasons are why my original answer argued that Mars would provide little protection against a strong event like that on Bastille Eay in 2000.

$\endgroup$
6
  • $\begingroup$ The link is to a paper on measuring the solar magnetic field, not the described work by Townsend. Your figures also make no reference to being specifically for the Mars surface environment, with solar radiation being halved by distance, blocked at night, and attenuated by the atmosphere. $\endgroup$ Commented Jan 6, 2022 at 1:48
  • $\begingroup$ @ChristopherJamesHuff - Odd, the DOI at the bottom of the first page of the paper is the one I had linked to originally (fixed it now). As for Mars, it has a very weak/tenuous atmosphere which would provide little protection from radiation. It also does not have an intrinsic magnetic field, which is additionally problematic. $\endgroup$ Commented Jan 6, 2022 at 13:35
  • $\begingroup$ Yeah...no. The atmosphere is very significant. As for the gyroradius issue, it's more complicated than that because solar protons follow a wide spectrum of energies and the induced magnetosphere and ionosphere have very significant effects. In all, there is a planetary shadowing effect (agupubs.onlinelibrary.wiley.com/doi/full/10.1002/2015JA022327). And even if true, this would only reduce the diurnal variation. $\endgroup$ Commented Jan 8, 2022 at 16:13
  • $\begingroup$ @ChristopherJamesHuff - If you are referring to SEPs when you say solar protons, the atmosphere of Mars is effectively meaningless (so too is the remnant magnetic fields). I was referring to the gyroradius of the core solar wind ions (note, not the thermal gyroradius, the ballistic one... I was wrong about this too). Compared to Earth, the Martian atmosphere would not provide any significant protection from SEP-level particles (nor would the remnant magnetic fields). For reference, a 100 keV proton has a gyroradius of ~4570 km, which is ~1100 km larger than the Martian radius. $\endgroup$ Commented Jan 10, 2022 at 14:03
  • 1
    $\begingroup$ @honeste_vivere you do remember that gyroradius is only relevant in a uniform magnetic field, which the environment around Mars most certainly is not. $\endgroup$ Commented Jan 10, 2022 at 14:17
3
$\begingroup$

You would be relatively protected on Mars, due primarily to the atmosphere. Directly overhead, you have ~16 g/cm^2 of CO2 atmosphere on average, far more along lines of sight closer to the horizon, and the entire planet blocking radiation from below, in all reducing radiation exposure by several orders of magnitude. There's also a significant day/night variation that correlates with atmospheric pressure variations, so necessary surface activities may be performed at night to reduce risk, and of course Mars has plenty of material for shielding habitation structures. The atmosphere being thinnest overhead, that's where you'd want the most shielding...for Martian architecture, think thick, overhanging roofs.

"The Solar Particle Event on 10–13 September 2017: Spectral Reconstruction and Calculation of the Radiation Exposure in Aviation and Space" provides this plot contrasting exposure in interplanetary space with that expected on Mars and at high altitude in Earth's atmosphere: this plot

Radiation Risks in a Mission to Mars for a Solar Particle Event Similar to the AD 993/4 Event provides an analysis for a much larger event, comparable to one that occurred in AD 993-994. The conclusion is that the atmosphere, planet itself, and some additional shielding will provide sufficient protection against comparable events. The atmospheric shielding is enough that acute short-term effects would be avoided even without shielding.

In short, Mars colonists will have to pay attention to solar weather and take reasonable precautions, but should not have any particular difficulty dealing with these issues.

$\endgroup$
2
$\begingroup$

The simple answer is: it won't kill immediately but depending on the length of the exposure before reaching a shielded area, it would definitely cause radiation sickness which would result in a whole bunch of symptoms similar to the symptoms recorded after the exposure to radioactive fallout during the Chernobyl reactor accident (like cancer, neural damage of some kinds, etc.). But all of those problems are long-term effects.

The armosphere and the suits the astronauts are wearing would already provide a relatively good shielding against a big part of the radiation. So I would assume, that exposure of several hours would definitely be not healthy, but managable.

An underground base would easily protect the astronauts from radiation, since the regolith is very good at blocking it, which is why some plans of mars bases include burrying modules under ground.

$\endgroup$
1
  • 5
    $\begingroup$ Your answer could be improved with additional supporting information. Please edit to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the help center. $\endgroup$
    – Community Bot
    Commented Jan 5, 2022 at 17:22

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.