In the vacuum of the interstellar space, there is nothing to lose momentum to (unless you hit something, which is unlikely), so no, a scout ship wouldn't lose momentum too quickly and turn everyone inside into borscht. It would cruise on inertia just like its mothership, and move alongside it, unless some external force acts on it differently than the mothership (e.g. entry into an atmosphere, with it providing drag on the scout ship), or the scout ship exchanges momentum with some other matter (e.g. reaction mass of own propulsion system, gravity assist, magnetic or solar sail, and so on), or the mothership itself (some sort of repulsions, like magnetism, photon pressure,...).
This is actually a big problem for proposed methods of interstellar travel, with perhaps most feasible one that is also capable of traversing such immense distances in reasonable time being beam-powered propulsion, where the source of momentum stays at the departure point and the ship is propelled on the power of deflected photons ($\mathrm{F} = 2\times \mathrm{P} / c$, in Newtons, for 100% sail reflectance, where $\mathrm{P}$ is total reflected power from the source in Watts, and $c$ the speed of light. Divide that with craft's mass in kilograms and you have acceleration that it would get from it. E.g. a 100 kg sail reflecting 50 GW at 100% reflectance, would accelerate at 3.36 m/s², so about 1/3 the gravitational acceleration on the surface of the Earth).
That comes with its own problems, of course, and I won't go into too much detail about it here, but most such proposed designs also call for a decelerating sail detaching from the mothership and acting as a reflector to reverse direction of the beam and decelerate the mothership in the opposite vector relative to its motion (sometimes called a brachistochrone turn, since it would be a constant acceleration system, but it is a bit of a mouthful and, in earnest, I've still not mastered pronunciation of this term). Of course, the deceleration sail is still being propelled in the direction of the beam while it reflects it, so the distance between the mothership and the deceleration stage would constantly increase. And this is where exchanged momentum goes to decelerate the mothership in a system like that. It's just an example though, but I've picked it because it's directly applicable to your question and perhaps not as intuitive how momentum is exchanged in it, while also demonstrating the need for it.
Point is, that all Newton's laws of motion of course apply also in the interstellar space:
First law: When viewed in an inertial reference frame, an object
either remains at rest or continues to move at a constant velocity,
unless acted upon by an external force.
Second law: The vector sum of the external forces $\mathrm{F}$ on an object is
equal to the mass $m$ of that object multiplied by the acceleration
vector $\mathrm{a}$ of the object: $\mathrm{F} = m\mathrm{a}$.
Third law: When one body exerts a force on a second body, the second
body simultaneously exerts a force equal in magnitude and opposite in
direction on the first body.
Consequence of that is that a smaller mass body like a scout ship detached from the mothership will require less force to decelerate, or conversely it would decelerate faster at same force applied in the vector opposite to its direction of movement than a more massive body, but unless it's acted upon by some external force, this won't happen and will just cruise alongside its mothership until something changes for it with respect to the mothership.
They would likely already have different mass, so you could then apply same source of decelerating force to each differently (e.g. with surface per mass for passive sails, burn rate per mass for own propulsion,...) and they will start moving away from each other. But the force of this decelerating force acting on its inhabitants would likely be small relative to its net momentum, so acceleration felt by its inhabitants would also be small. Again, unless you hit a solid body at largely different relative velocity. Then, they would turn into borscht and the energy released upon impact equals $E_\text{k} =\tfrac{1}{2} mv^2$, so as you can see, relative velocity matters a whole lot more than the mass of the object, tho it's still relevant, too. But that's a different matter (no pun intended).