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Are there libration points in a restricted 4-body problem (system of three orbiting bodies of significant mass, plus the libration point orbiting body)? If so, how many of them exist and where are they located?

Jovian system must have its periodic or quasi-periodic libration points. Would two or more of its Galilean moons in orbital resonance with Jupiter play a role despite their low masses relative to the primary, or is an orbiting system of 3 bodies of significant mass required for such libration points to remain stable? How does such a system's effective potential change and could any of these libration points be periodic?

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    $\begingroup$ This may seem a bit cheeky, but what exactly is wrong with our solar system? It is a system of multiple orbiting bodies, with many Lagrangian points. The Sun/Earth/Moon system is the classic 3 body system from the 3 body problem, with well studied lagrangian points. 2 moons of Saturn, have a moonlet in their L4 or L5. I don't think this is the answer you're looking for, but if the question is taken literally it is the answer. $\endgroup$ – Blake Walsh Jul 31 '15 at 20:03
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In a system with libration points, none of the bodies move relative to the point. Therefore, the Earth/Moon points are not valid 4-body solutions, because they move relative to the Sun. For true 4-body or higher n-body systems that are not simply coupled 3-body systems, we have to look at Klemperer rosettes and similar arrangements. If the barycentre in the middle is not occupied, this would be a libration point. If we use a rotating frame of reference, we can model inertia as a fictitious force acting away from the middle. If an object occupies the barycentre, an equivalent of the L1 point will exist between the centre and one of the objects in the orbiting polygon. That is not a stable point, and the many other possible points are not stable either. As the inertial force of an object stationary in a rotating frame of reference grows linear with distance, and the gravitational influence from the object with the inverse square law, a equilibrium where this forces cancel out exist on every axis of symmetry of the system.

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