I am trying to create a graphic with the sun, moon, and earth in the same frame as if looking from the end of the Apex node, assuming a 100,000 km tether, but with the correct sizes, placement, axis angle and color. Something like this..... enter image description here

This graphic has issues....
1) It is not from the point of view of the Apex node at 100,000.
2) I have no idea if there is ever a time in the orbits of the earth, moon and sun where they would close enough to preserve the scale.
3) I have no idea if the colors are correct.
4) In the real world the tether would loose visibility quickly as it get farther away from the view point. But how soon? 100km out?
5) It is not to scale.

Question 1) Where would a non-expert go to get answers?
Question 2) Is there software that can do this?

  • 1
    $\begingroup$ Can you explain a little more what the "tether" is? Does it need to be in the picture? As for software, I would suggest Celestia ( shatters.net/celestia ) might help, it's a free download and will allow you to try view points. $\endgroup$ – Andy Apr 11 '16 at 14:56
  • $\begingroup$ A professional author explains best space.com/24739-space-elevator-tether-technology.html $\endgroup$ – paulhr Apr 11 '16 at 15:06
  • $\begingroup$ The site at the link is not working yet....."shatters.net is a totally awesome idea still being worked on. Check back later." $\endgroup$ – paulhr Apr 11 '16 at 15:09
  • 1
    $\begingroup$ Celestia itself is a download (from that page) that runs under Windows. If you do a general web search for "Celestia space elevator" you will find a people have already produced models and images of this popular subject. Well worth a look... $\endgroup$ – Andy Apr 11 '16 at 15:21
  • $\begingroup$ It seems the h t t p : / / w w w ." prefix, without the spaces in between, is required .shatters.net/celestia $\endgroup$ – paulhr Apr 11 '16 at 16:52

enter image description here

I would like to thanks Andy for giving me the link to the Celestia software that got me the answer.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.