Let's imagine we have delivered a very long/tall tower into orbit. It's a rigid construction, a couple hundred kilometers long, at altitude where air friction is entirely negligible.
If we place it in circular orbit - its center of mass moving at just the right speed for its altitude - but we rotate it to some random angle to the surface, and leave it like that, giving it spin of 1 revolution per day so that - neglecting tidal forces - it would naturally remain in the same orientation to the surface.
It won't stay like that. The linear velocities of all its points relative to Earth are about the same (the bottom end's minimally lower, upper's minimally higher due to that 1RPD spin, but these should be negligible differences).
Now, the end that happens to be at lower altitude, moves slower than orbital velocity proper for that altitude and will tend to be pulled downwards. The other end, exceeding circular orbit's velocity for its altitude, will be pulled upwards. Our tower starts spinning.
What's the stable equilibrium position at which it would remain still - always facing Earth at the same angle?