In addition to Undo's answer, I'll try to give a "zeroth order", back of the envelope analysis for this:
First, from my answer here, we have $$T=DB=2DM/R^3$$ where $T$ is the torque applied by the torquer, $M$ is the magnetic moment of the Earth (about $7.96\times 10^{15}~\text{tesla}\cdot \text{m}^3$), $D$ is the dipole induced by your torquer, and $R$ is the distance from the center of Earth's dipole.
Now, mechanics tells us that $$T=I\alpha$$ where $I$ is the moment of inertia and $\alpha$ is angular acceleration. We'll take $I_{xx}=127908568~\text{kg}\cdot\text{m}^2$ from here for our purposes, and let's say you want to impart a modest angular rate of $0.05~^{\circ}/\text{sec}^2\approx 0.0009~\text{radians}/\text{sec}^2$.
So, the magnetic dipole required in this case would be $$D=\frac{I\alpha R^3}{2M}=\frac{127908568\cdot 0.0009\cdot (6478*1000)^3}{2\cdot 7.96\times 10^{15}}\approx 1.966\times 10^9~\text{A}\cdot \text{m}^2$$
This is a massive dipole. If we calculate the dipole moment of a wrapped coil with $N$ turns as $A\times I\times N$, and even assume a fairly massive 1 meter cross sectional area, and a generous 10 Amps of current, a torquer using 1 mil copper wire would be 1 meter long and have a layer of copper 13 cm thick. This would weigh about 1200 kg, which is pretty damn heavy. Consider this with Undo's more qualitative points, and it's starting to look like a bad idea, even if it's not physically impossible.