I was wondering if, and how, one can tell from the values in a TLE whether an orbit is LEO, MEO, HEO, or GEO. I'd like to do this in code eventually, so any formulas or threshold values would be much appreciated.
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3 Answers
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According to Wikipedia, field 8 of TLE line 2 is the "mean motion in revolutions per day"; you can determine the orbital period from this.
For geosynchronous orbit, you should expect 1.0 revolutions per day (in fact, due to complexity in the definition of "day", they're very close to 1.0027 as a rule).
LEO defined as < 2000 km altitude should get periods between 84 and 127 minutes (i.e. ~11 to ~17 revolutions per day).
MEO defined as 2000 km to geostationary would then be 1-11 revs a day.
HEO defined as higher than geostationary would be less than 1 rev per day.
Highly elliptical orbits complicate this, obviously; it's up to you how you want to classify a satellite with perigee in LEO and apogee in MEO. You can derive the SMA from the period, and the eccentricity is in line 2 field 5, if you want the actual perigee and apogee.
answered Oct 19, 2017 at 21:46
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$\begingroup$ Very nice. Had never seen the fields broken down. $\endgroup$ Oct 19, 2017 at 22:03
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1$\begingroup$ At least in the fields I have experience in, HEO refers to Highly Eccentric Orbit or High Eccentricity Orbit. I don't think I've ever seen it used to refer to High Earth Orbit. Those are rare - as a collective term, I think we usually refer to them as super-sync. $\endgroup$ Oct 26, 2018 at 17:41
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The TLE gives mean motion ($n$) in $\frac{rev}{day}$. This needs to be converted to $\frac{rad}{s}$ which can be accomplished by multiplying the $n$ TLE value by $\frac{2\pi}{86400}$.
Therefore, to go directly from $n$ in TLE to the semi-major axis $a$. We can use the following formula: $a=\frac{u^{1/3}}{\frac{2n\pi}{86400}^{2/3}}$.
From here, orbital regimes can be determined ($100km<a\leq2000km$ means LEO, $2000km<a<35786km$ is MEO and GEO is ~$35,786km$).
There are other complexities around eccentricity, and for GEO you'll want to include bounds on inclination.
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$\begingroup$ For GEO it might be more intuitive and accurate to select directly on mean motion directly (e.g. ~1.0027 rev/day for synchrony to a sidereal day) rather than to derive the Eulerian (and therefore approximate) value for $a$. Even out there J2 has a 100 ppm effect on the period (you can't just use $\mu$). Equation for orbital period around oblate bodies, based on J2? $\endgroup$– uhohOct 26, 2018 at 4:05
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1$\begingroup$ I would disagree about being more selective for GEO - there are lots of GEO objects which are oscillating about the GEO orbit (old satellites, debris) and these to me also count as GEO. D'oh on the altitude - definitely don't forget the 6378! $\endgroup$– DiamondOct 26, 2018 at 11:51
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$\begingroup$ If it were me I would give the best possible information first, then offer the various options for simplifying. It's just a thought. Now it's at least here in comments anyway. $\endgroup$– uhohOct 26, 2018 at 11:57
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You can download TLE data for each of these orbit regimes separately with the click of a link at https://www.space-track.org/#recent after registering and agreeing to the terms of the site. The definitions used there are:
- HEO: Eccentricity > 0.25
- GEO: 0.99 <= Mean Motion <= 1.01 and Eccentricity < 0.01
- MEO: 600 minutes <= Period <= 800 minutes and Eccentricity < 0.25
- LEO: Mean Motion > 11.25 and Eccentricity < 0.25
In this usage, HEO definitely means Highly Elliptical Orbit, not "High Earth". Note also the fairly restrictive definition of "Medium", for mean motion between 1.8 and 2.4 , such that there are portions of the parameter space that don't fit any of these names. This is not really a problem in practice, as there are very few actual objects having orbit elements falling into one of the unnamed regions.
u. Here is the answer space.stackexchange.com/a/18291/51924. $\endgroup$