# Will an array of multiple ion engines still be more efficient than a single chemical engine?

I was just thinking the other day and got this idea out of my head. I'm not an aerospace expert or anything even close to it, so please understand even if this turns out to be a really basic question:

Provided that the power issue can be solved, would an array of multiple ion engines (or a scaled up version of one engine for that matter) that has the same amount of thrust with that of a traditional chemical engine, still be more efficient than the chemical engine?

I am well aware that given the T-W ratio of the ion engines, it would still make it impossible for them to be used as first stage engines no matter how many you strap them together, but what about for the space stations or reusable interplanetary vehicles?

• With high specific impulse engines like ion engines, you'd be using a continuous burn instead of Hohmann. Burning continuously means you arrive faster for the same thrust, or take the same time for far less thrust, at the cost of using much more delta-v (~30 km/s vs ~6km/s for Mars) which is fine since you get much more delta-v for each kilogram of propellant with an ion engine. However, with an unlimited, efficient, easily contained power source, a high temperature thermal rocket would also be vastly superior to a chemical rocket. – timuzhti Oct 18 '18 at 8:29
• This question is poorly posed. What you should be comparing is time and mass performance for specific orbital maneuvers. The whole point of ion engines is that they are low thrust. Trying to scale up ion engines to the thrust of some chemical engine misses the whole point. An ion engine could get to mars using less thrust for longer, but still end up there before the chemical rocket. It would also get to mars with more mass than the chemical rocket. – Knudsen Number Mar 13 '19 at 23:54

While this seems like a good idea at first, you very quickly run into the main problem with ion engines: their tiny thrust.

Let's compare a typical ion engine from the Dawn mission and an upper stage commonly used for interplanetary injections, the Centaur Upper Stage with its RL10 Hydrogen-Oxygen engine.

Ion Engine

RL10 C-1

We can see that the RL10 generates on the order of 1 million times more thrust for around only 20 times more mass. This means that we're going to need some 8 million kg of ion thrusters to produce the same thrust – equivalent to about 2.5 fully fueled Saturn V's.

It gets even worse when we consider the fact that this massive array of thrusters will require a similarly enormous amount of extra plumbing and structural support for it to run. Not to mention the difficulties in trying to squeeze a million engines onto the mounting plate at the base of the stage.

This will clearly negate any benefit we gain from using a higher-efficiency engine.

Of course, there will be a break-even point. A very quick-and-dirty approximation says that if we modified a Centaur Upper Stage to give it ion engines and filled the tanks with xenon (this obviously wouldn't actually work), an array of ~500 ion thrusters would give a 1000 kg payload about the same delta-v as a single RL10, albeit at a much lower thrust.

So any useful benefit to be gained by using ion thrusters will involve far, far fewer than this break-even point which is what we see on existing spacecraft. For example, Hayabusa2 has four ion engines on a gimbal mount, three of which can be run simultaneously.

• Probably the breakthrough would come with streamlined, massive off-planet manufacturing. With a good, streamlined manufacturing line building an array of some 5000 engines (weighing 5% of what currently they do) would be much smaller a problem than getting them into orbit. But if you harvest resources off asteroids and build them in space... unfortunately we're nowhere near that. – SF. Oct 9 '18 at 12:23
• This is wrong. Your Centaur upper stage will give you a higher peak thrust, but not for very long. And you're in space, so why do you need a high peak thrust anyway? The ion engine will give you far more delta V per kg. – jamesqf Oct 9 '18 at 15:49
• @jamesqf I need a high peak thrust because that is what the question asked for - I use the Centaur as an example of a 'traditional chemical engine'. Yes, an ion engine will give far more delta-v per kg, but an array of 1 million ion engines will not, due to the additional mass they entail. – Jack Oct 9 '18 at 16:00
• @xyious: It doesn't need to get off the ground, because it's already in space :-) – jamesqf Oct 10 '18 at 2:26
• @jamesqf again - an ion engine wouldn't mass all that much, but "an array of multiple ion engines that has the same amount of thrust with that of a traditional chemical engine" would consist of millions of engines and would therefore be incredibly massive. The 8.2kg example I give is the mass of just the engine, not of any power supply or other necessary hardware, so if you want more than one of them you will be compromising your efficiency due to the extra dry mass. – Jack Oct 10 '18 at 7:41

Why is an ion engine more efficient than a chemical engine? The exhaust velocity is much higher.

If the power issue can be solved and each ion engine of the bundle has the same high exhaust velocity, the bundle is still more efficient than a single chemical engine.

But what about weight? To provide more power will increase the weight of the vehicle as well as the additional ion engines. To compensate the increased weight more ion fuel is necessary. To store more fuel a larger and heavier tank is needed.

So if there is enough time for slow acceleration with a single ion engine over years the total costs are lower than for the bundle of engines delivering the same delta-v in months. You will need a larger first and second chemical stage to lift that vehicle into orbit where the ion engines may take over.

Thrust is the wrong measurement to use for this comparison, as is thrust to weight. What matters is the Specific Impluse $$I_{\text{sp}}$$, which is a measure of the ability to change momentum per unit of propellent.

The RL10C has a specific impulse of 450s, while the Dawn engine is over 3,000, in other words, the Dawn engine can do over over 6 times more work per unit of propellant though its lower thrust means it will take longer to do it, but unless you are trying to escape a gravity well, there is no hurry. One source of the difference is the fact that a chemical motor includes its power source in the mass of its propellant through oxidation, while for an ion motor the power comes from an fission - reactor or solar panels etc. Now the weight of the engine itself starts to make a big difference. To use Jacks example, the 200Kg RL10C with 799Kg of fuel and 1 kilo of payload would produce a $$\Delta v$$ of:

$$\displaystyle \Delta v=v_{\text{e}}\ln {\frac {m_{0}}{m_{f}}}$$

Where

$${\displaystyle v_{\text{e}}=I_{\text{sp}}\cdot g_{0}}$$

$$\displaystyle \Delta v=450 \times 9.8 \times \ln {\frac {(200+799+1)}{(200+1)}}$$ $$= 7075ms^{-1}$$

The 8.3Kg Dawn engine and 2.5Kg of propellant with the same payload would get you

$$\displaystyle \Delta v=3000 \times 9.8\ln {\frac {(8.3+2.5+1)}{(8.3+1)}}$$ $$= 6999ms^{-1}$$

but would be much cheaper to get 11.8 kilos to LEO so that you can accelerate a 1kg payload to 7,000 m/s then getting 1000kgs to LEO to accelerate the same payload to the same speed.

Adding more engines does not change the Specific Impluse, it just increases the fuel flow (ie it increases the thrust), but since you are now moving the weight of the additional engines, it reduces your final $$\Delta v$$, as rocket scientists love to say, you get there faster but not as fast, (you reach a lower velocity but you reach it sooner). Engines which produce thrust in excess of their own mass can be combined to use that excess thrust to accelerate out of a gravity well, however, ion engines do not have any excess thrust so combining them has limited benefits.

Doing this with two chemical engines would give: $$\displaystyle \Delta v=450 \times 9.8 \times \ln {\frac {(200+200+799+1)}{(200+200+1)}}$$ $$= 4833ms^{-1}$$

Two ion engines would give you:

$$\displaystyle \Delta v=3000 \times 9.8\ln {\frac {(8.3+8.3+2.5+1)}{(8.3+8.3+1)}}$$ $$= 3904ms^{-1}$$

• @Jack, both you and the OP are attempting to use T-W to compare rocket motors and as I show, the correct approach is to compare specific impulse instead. The OP asked about efficiency which I think I answered by giving the two engine configurations that produce the same end result (1Kg payload at 7Kms deltaV). – Paul Smith Oct 10 '18 at 15:18