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I am not sure I understand the Time dilation correctly but if mass has dirrect impact on time...than lets consider cosmological event - one orbit of planet Earth around Sun. This event will person on Earth experience as time equal to lenght of one year but the atomic clock located on Mars will show something else. The person on Mars will not experience this cosmological event as the same time period...So my question is what is the difference? I suppose with atomic clock can measure the difference. Also Sun the obviously the biggest evelement, but Mars is further than Earth...

Unfortunately the mathematic behind this is so complicated for me and I cant even beging to imagine what all I should consider...So if anyone can give me at least some estimation..? Thanks

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From my answer to Parker Solar Probe passing extremely close to the Sun; what relativistic effects will it experience and how large will they be?:

From here (or here if you are ambitious) the lowest order terms to the relativistic frequency shift of a clock in orbit around a gravitational body are:

$$ \frac{\Delta f}{f} \approx -\frac{\Phi}{c^2} - \frac{v^2}{2c^2} = -\frac{GM}{r c^2} - \frac{v^2}{2c^2},$$

where the first term is the gravitational shift and the second is time dilation.

Plugging the standard gravitational parameter $GM$ and radius $r$ of Mars into the term $-\frac{GM}{r c^2}$ I get 1.4E-10.

That means that the shift in the rate of a clock due to Mar's surface gravity is -0.14 parts per billion. For Earth it's -0.69 ppb.

But the problem is more complicated. So let's include some more correction terms.

Mars and Earth are moving fast in orbit around the Sun, and they sit in the Sun's gravitational potential. Let's look at the relative sizes of these terms:

                              All values x1E-09
        local gravity  local rotation     Sun's gravity      orbital velocity 
Mars       -0.140          -0.0003            -6.478                -3.239
Earth      -0.695          -0.001             -9.870                -4.935

To answer the question: -0.140 minus -0.695 equals +0.555 parts per billion, due only to the local planetary gravities; things are faster on Mars than on Earth by 555 parts per trillion.

But the big effects have to do with the heliocentric orbits.

-0.140 + -0.0003 + -6.478 + -3.239 minus -0.695 + -0.001 + -9.870 + -4.935 gives +5.644.

Overall: time is faster by about 5.6 parts per billion on Mars relative to Earth, but that's mostly due to orbiting closer to the Sun.

Compare that to roughly ~430 pars per billion (half of a ppm) for the Parker Solar Probe when it swings close to the Sun!


Those are typical values and not meant to be accurate to the number of decimal places shown because both the Earth and Mars are moving in elliptical orbits, and so each one varies differently with time. I've rewritten the equations in that answer incorporating the vis-viva equation for a more convenient form shown below, but it would be better to use proper state vectors .

$$ \frac{\Delta f}{f} \approx -\frac{GM}{c^2}\left(\frac{2}{r}-\frac{1}{2a} \right).$$

edit: How would this frequency difference be measured?

One way would be to put an ultra-stable clock on each planet that emitted one pulse every second (local time) that fired a laser into space. A ship could time the difference between the two, correct for the light-time it took for the laser. As the OP calculates after one year the difference would be about 0.17 seconds.

However, if you started flying around to check each clock yourself and compare it to your portable ultra-stable clock, the problem becomes much more complicated to solve, and beyond what I'm able to explain with any confidence... okay, absolutely unable to explain even a little. ;-)

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    $\begingroup$ Thanks a lot. Very nice and comple answer? So to say it in seconds - each year will be around 0,17 second shorter than on Earth...? Is that correct? $\endgroup$ – Miroslav Řešetka Jan 15 at 9:34
  • $\begingroup$ @MiroslavŘešetka yep, I get about the same thing, 0.177 or about 0.18 seconds. $\endgroup$ – uhoh Jan 15 at 9:38
  • $\begingroup$ Thanks. If I have following question(s) about time dilatation from the perspective of the time on the way between E and M sould I open a new one or is it ok to ask here? $\endgroup$ – Miroslav Řešetka Jan 15 at 10:14
  • $\begingroup$ @MiroslavŘešetka Comments should be used for clarifying the post they are under. There's no firm rule so sometimes people do a short, related follow-up in comments, but asking a new question is always better and gives more visibility to future readers and more people a chance to write a new answer. $\endgroup$ – uhoh Jan 15 at 10:26
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    $\begingroup$ @MiroslavŘešetka these are deep and broad questions, and there are websites and blogposts and even books on the subject. For specific questions about what happens if you fly somewhere, stay a while, and then come back, I think you'll find it has been asked and answered a few times in Physics SE and it wouldn't make sense to re-answer it much more poorly here. I've made an edit at the bottom of the question. It's possible others will add answers to your question here as well, so stay tuned! $\endgroup$ – uhoh Jan 15 at 12:27

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