tl;dr: I don't think there is any scenario where you can strike the Moon with low velocity by using a small impulse to leave orbit. You can hit sideways with an orbital velocity of about 1680 m/s, or vertically with escape velocity the square root of 2 larger at 2376 m/s.
Let's say I launched something into lunar orbit with minimal of propellant - just enough for trajectory corrections and then a final push to de-orbit.
From low lunar orbit
When in orbit around Earth, say at 400 km, "a final push to de-orbit" would be a small impulse to lower the perigee to about 100 or a little higher. Then each time the spacecraft passed near perigee it would loose a little more velocity due to drag, slowly circularizing near perigee. After that, it would spiral due to drag and eventually reenter the main part of the atmosphere and quickly either burn up, or fall to the ground if it had proper heat shielding and aerodynamics.
But the Moon is tricky. If it were a nearly perfect gravitational sphere, then your burn would lower the perilune to just above the average lunar surface where it would strike whatever boulder or crater rim might be sticking up. This would happen at the lunar orbital velocity given by the vis-viva equation
$$v= \sqrt{GM/a}.$$
The standard gravitational parameter of the Moon $GM$ is 4.905E+12 m^3/s^2 and the semimajor axis $a$ would be the lunar radius 1.737E+06 meters. That puts the velocity at about 1680 m/s.
Since the Moon has quite a lumpy gravity field all you need to do is to bring the spacecraft to a very low orbit and just wait. Due to gravitational perturbations, or those from the Earth and Sun, eventually its constantly changing orbit will bring it into contact with the surface.
There are no small orbital corrections from a low lunar orbit that can bring it down within 30 degrees of vertical. You'd have to do a major burn to loose most of that 1680 m/s of orbital velocity very quickly, so that it would just "fall straight down".
From high lunar orbit
If the Moon were all alone in space, you could put yourself in an absurdly high lunar orbit, let's say 1 million kilometers. At that altitude your orbital velocity would be only 70 m/s and a delta-v equal to that would stop you in your tracks. However, then you'd fall towards the Moon and accelerate.
Your velocity at impact dropping from an altitude $a$ to the lunar radius $R$ would then be
$$v= \sqrt{2 GM\left(\frac{1}{R} - \frac{1}{a}\right)}.$$
If you plot those versus the starting semi-major axis, you can see that the delta-v you'd need to fall out of orbit, which is the orbital velocity, drops with increasing altitude, but the resulting impact velocity due to acceleration towards the Moon rapidly rises.
There's no gentle delta-v followed by a gentle impact.
What about a clever 3-body orbit?
But what if I know about the chaotic 3-body orbits of minimoons that uses both the gravity of the Earth and the Moon, and I wanted to look for a crazy orbit that starts near a stable orbit, but "goes chaotic" and eventually touches down on the surface of the Moon, or slows very close to it?
This doesn't happen. I think there is a good Stack Exchange Q&A on this somewhere in Space Exploration, Astronomy, or Physics, but I can't find it.
The argument goes like this: orbits work just as well forwards and backwards in time. So if such an orbit existed, then the backwards scenario would also have to be possible; you'd be able to hold a rock near the surface of the moon, give it only a slight nudge, and it would mysteriously start flying away from the Moon and end up in a high orbit.
That doesn't happen, it just falls to the surface with a silent but none-the-less perceived thud.