I like to play with the notion of cyclers. One type of cyclers is a circular orbit crossing an elliptical orbit, both with the same period. On this comic book page the Cheng Ho is such a cycler.
The geometry of orbits about the sun and around the earth are the same so I'll leave the labels at A.U. and years.
Here for simplicity's sake I set both the semi major axis of the ellipse and radius of the circle at 1 A.U.
Area of the circle is π r^2. By basic trig and pythagorean theorem the angle of the arc from A to B is 2 * asin((1-e^2)^1/2). So the area of the wedge is asin((1-e^2)^1/2) r^2.
Area fractions of the elliptical orbit is trickier. We use Kepler's trick of stretching the ellipse along the small axis to make it a circle. This doesn't change the fraction of area occupied by pink and blue parts.
I think you can see that departing from A the two orbits would arrive at B at different times. So they'd miss each other at B. However they would both arrive at point A at the same time after a full orbital period.
Although someone jumping from a circular I.S.S. orbit would be in an ellipse with an eccentricity very close to zero. That is to say, darn near circular. I haven't done the math but I expect he'd land back on the I.S.S. in 45 minutes but probably a few meters from where he jumped.
Also accelerating in a direction perpendicular to your velocity vector would increase velocity and thus the semi major axis of your ellipse. You would no longer be in orbit with the same period as the orbit you departed. But, again, the velocities achievable with a human jump would put you in an orbit only negligibly different from the original orbit.