The Voyager 1 loses speed gradually after gaining speed from gravity assist. Is the external thrust is applied in the opposite direction to move closer to the planet, or does the spacecraft lose its momentum after the sudden rise in speed?

Animation showing Voyager 1 gravity assists with speed

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    $\begingroup$ throw a ball up. Why does it slow down? $\endgroup$ – njzk2 Mar 2 '20 at 22:40
  • $\begingroup$ Or in other words: Part of its kinetic energy is converted to gravitational potential energy. $\endgroup$ – Michael Mar 5 '20 at 11:01

It's the gravitational attraction of the Sun. Voyager is moving away from the Sun and is pulled back by its gravity. Since Voyager is not moving directly away from the Sun, it's trajectory also curves.

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    $\begingroup$ Note that, for simplicity's sake, Voyager is being affected by the Sun the same way a ball is being affected by the Earth if you throw it up (but not straight up in the air. It follows a parabolic trajectory in which it gradually slows down (vertically speaking), and were it to come to a complete (vertical) stop, it would then fall back down, i.e. towards the Earth (ball) or Sun (Voyager) again. $\endgroup$ – Flater Mar 3 '20 at 12:03
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    $\begingroup$ @Flater This is almost right. A ball only follows a parabolic trajectory if you ignore the curvature of the Earth, or fire it at exactly the right speed. The trajectory of Voyager is actually a hyperbola. Also note that, since the Sun's gravity gets weaker the further away from it you are, Voyager 1 will decellerate less and less as time passes, and never actually fall back. $\endgroup$ – Steve Linton Mar 3 '20 at 17:25
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    $\begingroup$ In my defense, the ball throwing example was intended on a much smaller scale that one in which the Earth's curvature matters. Just exactly how far are you able to throw a ball!? $\endgroup$ – Flater Mar 3 '20 at 17:53
  • $\begingroup$ Curvature doesn't play a role for the ball .. but ballistic influence due to atmospheric drag .. hence artillery calculates in atmospheric drag to hit a certain spot $\endgroup$ – eagle275 Mar 5 '20 at 12:40

Additionally, the probe has just passed a large planetary body with its own gravity well. The probe has to climb up out of that planet's gravity well which costs momentum.

There is a net gain in momentum overall, the probe is leaving with more momentum than it entered the slingshot manoever, but the highest velocity is about where the probe is moving parallel to the planet's surface.

  • $\begingroup$ It looks like the whole slingshot maneuver is instantaneous in the animation. $\endgroup$ – user253751 Mar 3 '20 at 12:10
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    $\begingroup$ @user253751: It's definitely not instantaneous. Take a look a the timescale in the upper left of the animation. $\endgroup$ – Michael Seifert Mar 3 '20 at 12:46
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    $\begingroup$ @MichaelSeifert instantaneous in the animation. $\endgroup$ – user253751 Mar 3 '20 at 12:50
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    $\begingroup$ @user253751 It seems to use about 3 frames. Enough that my brain can interpolate the animation into something meaningful, but --- as you say --- not enough to query any internal properties of the maneuver. $\endgroup$ – jpaugh Mar 3 '20 at 17:08

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