6
$\begingroup$

How does a rocket know when to do apogee kick motor. Do they orbit once to find highest point?

$\endgroup$
  • 2
    $\begingroup$ Your question looks very interesting (maybe too broad, but I think it is not). However, your first sentence shows some formulating problems, I suggest to improve it ASAP. $\endgroup$ – peterh - Reinstate Monica Jul 8 at 12:10
  • $\begingroup$ @peterh, let's please not micromanage posts. If the post isn't obviously bad, and it isn't, and you yourself concede it, then let it be. It's supremely off-putting to always have a moderator nitpick on every question just because it could be better. Of course it could be better. All the posts could be better, and some especially so. Just accept it and let it be unless there is some major fundamental problem with the post. Please. $\endgroup$ – Alex Jul 10 at 5:00
  • $\begingroup$ @Alex This problem is not little - important part of the question is hard to understand. The task of a reviewer, but all experient user readinf the post, is exactly this: helping improvement, either by edits (or edit suggestions), or by advices in comment. Letting it in its current form would be bad, and not intervening. $\endgroup$ – peterh - Reinstate Monica Jul 10 at 5:48
12
$\begingroup$

There are multiple methods by which a satellite may determine where it is.

The traditional approach is ground tracking. As David Hammen has mentioned, in this case ground stations detect where the satellite is and how it is moving. This information is then used to calculate the orbit. If necessary, the satellite may be told about this orbit, but more likely the information is used by the ground station to decide what commands to send to the satellite and when. A downside is that this information is only available when the satellite is within the field of view of a ground station, and it is rather imprecise (several km for Low Earth Orbits and 50 km for geosynchronous orbits). For Low Earth Orbit the Global Navigational Satellite System (GNSS) is more accurate.

The NASA Tracking and Data Relay Satellite System (TDRSS) adds to this a constellation of satellites in such a high orbit that with just two satellites one can provide tracking data coverage for 85% to 100% of low earth orbits (Larson and Wertz), It is also much more accurate with accuracy of about 50m (3 sigma), and commonly used.

There are several autonomous or semi-autonomous systems, where the satellite determines its position without relying on a ground station. Some are in common use, others are experimental.

The Global Navigational Satellite System (GNSS), such as GPS, GLONASS, GALILEO, works well in Low Earth Orbit (nowadays used a lot), difficult in Geostationary orbit, unavailable in extraterrestrial orbits.

The Microcosm Autonomous Navigation System (MANS) is fully autonomous. It uses attitude-sensing hardware, looking at Sun, Earth, and Moon to provide real-time attitude and position information. The principle is similar to determining your position by looking at several landmarks. This method has been tested, but is not in common use. It could be used for spacecraft in solar orbits or orbits around other planets as well. For a novel method based on an x-ray sextant-like technology, see Is NICER/SEXTANT the first civilian "spacecraft" to determine it's own position in space without GPS or uplinked data?.

In principle, a satellite in Earth orbit could use landmark tracking to determine its position, but this is not in common use for satellite orbit determination (it is, however, frequently used for correcting the geolocation of images taken from satellites). Determining the distance to the transmitting ground station by signal delay is easier (I don't know if this is used in practice), but has the same limitation as traditional ground tracking in that it only works when the station is in view.

Source and further reading: Larson and Wertz, Space Mission Analysis and Design, Third Edition (2006), §11.7.2 (page 501–507).

| improve this answer | |
$\endgroup$
  • $\begingroup$ I miss a sentence or two about electronic measurement of distance to ground stations by signal delay for up and down. $\endgroup$ – Uwe Jul 8 at 17:57
  • $\begingroup$ @Uwe Not familiar with that method (and not mentioned in my source), but it makes sense. I've added a point about it. $\endgroup$ – gerrit Jul 8 at 19:15
  • $\begingroup$ That method is very old, it was used for the V-2 rocket in WW2 and the Apollo mission. $\endgroup$ – Uwe Jul 8 at 20:04
  • 2
    $\begingroup$ @Uwe - That has long been the primary technique used by ground stations to determine the range (distance) to cooperative spacecraft. Range measurements, if available, are much more precise than are azimuth and elevation. Range rate measurement (also performed by ground stations) are even better than range measurements. $\endgroup$ – David Hammen Jul 8 at 20:40
  • $\begingroup$ What an excellent answer! I've just asked How exactly does TDRSS actually provide tracking? (Tracking and Data Relay Satellite System) $\endgroup$ – uhoh Jul 8 at 23:51
7
$\begingroup$

Most spacecraft do not know where they are. These spacecraft used time-tagged commands to initiate a burn, with the command either generated pre-launch or transmitted to the spacecraft from the ground. This approach does have issues, as witnessed by several spacecraft that have performed the right command at the wrong time.

Some spacecraft do know where they are, using a combination of data from global navigation satellite systems such as GPS and from inertial navigation sensors (INS). Relying only on INS is problematic; it's called ded reckoning (apparently short for deduced reckoning), but also sometimes called dead reckoning. As in using ded reckoning is a sure way to ensure that the spacecraft will soon be dead.

There are problems with GPS-only solutions as well. The observations aren't as frequent, there are issues with reflections ("multipath"), and velocities, which are critical for orbit determination, are not very accurate. Using a hybrid solution requires a rather complex Kalman filter, making the flight software expensive to develop, verify, and validate.

The complexity of the software and the need for expensive sensors is what makes the non-navigated spacecraft solution rather appealing.

| improve this answer | |
$\endgroup$
  • 2
    $\begingroup$ @gerrit When you see where Sun, Earth, Moon, and stars are, you get only directions but no distances. To calculate distances from directions is difficult and inprecise. $\endgroup$ – Uwe Jul 8 at 16:09
  • 2
    $\begingroup$ @gerrit this method can be used for attitude computation (i.e. orientation of the spacecraft). For orbit determination, GNSS is used if you're below the GPS belt regularly. Otherwise, ground stations with ranging capabilities are commonly used. There have been studies to use GPS signal in GEO birds but IIRC this requires some luck in receiving the signal. $\endgroup$ – ChrisR Jul 8 at 16:45
  • 6
    $\begingroup$ It's "dead reckoning", not "ded". See en.wikipedia.org/wiki/Dead_reckoning#Etymology $\endgroup$ – llama Jul 8 at 21:17
  • 1
    $\begingroup$ @llama - The term has been used both ways for a long time, and wikipedia is just wrong in this case. That article is far from the first time that wikipedia has been dead wrong (or in this case, ded wrong). $\endgroup$ – David Hammen Jul 8 at 22:23
  • 2
    $\begingroup$ @DavidHammen It's been used one way since the early 1900s, and the other since the early 1600s. There's plenty of evidence for "dead" being the original form and none for "deduced", per the publishers of the OED oxfordreference.com/view/10.1093/oi/authority.20110803095704179 $\endgroup$ – llama Jul 8 at 22:51
0
$\begingroup$

They don't know - they are injected into their path with a certain energy that determines their final trajectory at a certain height. Extremes are falling back to earth or having hyperbolic trajectories i.e. escaping earth's gravitational field. Furthermore, the inclination of the orbit can be used to control their relative placement re. to the earth's rotation for example resulting in so-called sun-synchronous orbits...

| improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.