I have to build an optimal trajectory between two orbits, which are in one plane, but with different semi-major axis, argument of perigee and eccentricity.

I've read different articles regarding the low-thrust optimization techniques, and now I'm looking for an example solution.

I would appreciate for a link/paper describing an example solution of the above problem.


I have an impulsive solution of this problem. Is it possible to convert the impulsive solution to the low-thrust?

  • 1
    $\begingroup$ I have not seen a conclusive proof even for the instantaneous variant: space.stackexchange.com/questions/16931/…, despite spending a lot of rep trying to attract a proof. $\endgroup$ – SE - stop firing the good guys Sep 1 '20 at 16:02
  • 1
    $\begingroup$ Also, the geometry of such orbits: math.stackexchange.com/questions/2168522/… $\endgroup$ – SE - stop firing the good guys Sep 1 '20 at 16:04
  • 2
    $\begingroup$ @SE-stopfiringthegoodguys - A bi-elliptical transfer to which you alluded involves three instantaneous burns, while a bi-tangential transfer involves only two. (A Hohmann transfer is a special case of a a bi-tangential transfer.) There are cases where a bi-elliptical transfer requires less delta V than a bi-tangential transfer, at the expense of taking more time, sometimes significantly more time. $\endgroup$ – David Hammen Sep 1 '20 at 16:22
  • 1
    $\begingroup$ @DavidHammen bi-elliptical transfers (with infinite apoapsis always minimizing delta-v), is in a sense also a bi-tangential transfer. It's just the "easy" solution. $\endgroup$ – SE - stop firing the good guys Sep 1 '20 at 18:40
  • $\begingroup$ @SE-stopfiringthegoodguys do you feel there is more to be learned on this question? space.stackexchange.com/q/16931/12102 If so I'm happy to add another bounty to it, but that might make more sense if the current answer were not accepted. $\endgroup$ – uhoh Sep 2 '20 at 2:31

There are too many variables, some of them infinitely variable, to arrive at the optimal burn plan. And then you need to incorporate that burn plan into something that can be carried out with a reasonably priced computer (US $200K is "reasonably priced) than can handle high level radiation. This is not going to be a state of the art computer.

What you can do is use techniques that come close to the theoretical optimum but with constraints that keep the profile manageable by a not quite up to date computer. Mischa Kim's PhD thesis suggests using Adaptive Simulated Annealing. Markov Chain Monte Carlo is very similar to simulated annealing, and is perhaps easier to set up. Another related approach is a particle filter. All use a variant of the Metroplis algorithm, aka the Metropolis-Hastings algorithm.

Suppose you know that it will take multiple orbits from the initial orbit to the final desired orbit. In this case, you do not want the spacecraft firing continuously. You instead want the spacecraft to take advantage of the Oberth effect. In the case of very low thrust, this means firing for roughly 2/3 of the orbit, roughly centered around periapsis, plus perhaps a final finite thrust when the spacecraft nears the desired orbit.

I would do this in stages. First assume impulsive burns at periapsis, with the impulse equivalent to what could be achieved by the finite thrusters over the course of 2/3 of an orbit, with a penalty for gravity losses. Use a search technique to find a tentative multi-burn solution. This becomes the initial guess for the multiple finite burn solution. The transformation from impulsive burns to finite burns will miss the target.

So now you use similar techniques to refine the transformation. The nice thing about the Metropolis algorithm, and its variants, is that the randomness applied to tentative solutions kicks things away from local minima that in fact are lousy solutions.

  • $\begingroup$ I have an impulsive solution. Is there a way and would it be correct to convert it to a low-thrust solution? $\endgroup$ – Leeloo Sep 2 '20 at 12:49

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.