2
$\begingroup$

Laser ranging of the Moon is usually done with a Q-switched pulsed laser fed into a big (1 or 2 meter diameter) telescope as a collimator in order to get a tight beam all the way to the Moon in hopes of maximizing the amount of light returned by a small retroreflector array.

What beam shapes to these systems generate? Are they under-filling the aperture with a mostly Gaussian beam from a spatial filter resulting in a Gaussian profile at the Moon, or do they do some beam shaping to get most of the power to more uniformly illuminate the telescope's aperture, resulting in more of an Airy disk?

$\endgroup$
1
  • 1
    $\begingroup$ Can't comment for all but the main LLR site currently is Apache Point Observatory Lunar Laser-ranging Operation described in this paper - Section 3.2.1 seems to be what you want. $\endgroup$ Commented Feb 27, 2021 at 1:00

1 Answer 1

4
$\begingroup$

Thanks to @astrosnapper's comment I've looked at section 3.2.1. of Murphy et al. 2007 APOLLO: the Apache Point Observatory Lunar Laser-ranging Operation: Instrument Description and First Detections.

APOLLO uses the Apache Point 3.5 meter telescope for both transmit and receive, a rotating transparent disk with a mirrored spot on it rotates 20 times per second for T/R switching.

  • Primary is 3.5 m diameter, f/10 at the Nasmyth ports ref
  • 1.1 arcsecond median image quality near zenith
  • 90 ps FWHM Nd:YAG laser operating at 20 Hz and 115 mJ/pulse
  • photon return rates approaching one photon per pulse
  • requisite number of photons for one-millimeter normal (ranging) points collected on few-minute timescales.
  • best performance to date approx. 2500 return photons from the Apollo 15 array in a period of 8 minutes. Avg. return rate then about 0.25 photons per shot, peak of 0.6, Approx, half photons arrived in multi-photon bundles, largest containing eight photons.
  • APOLLO brings LLR solidly into the multi-photon regime for the first time.

Telescope specs

From Things to know about the ARC 3.5m telescope

Uncorrected optical design
GENERAL LENS DATA:

Surfaces        :           5
Stop            :           1
System Aperture :Entrance Pupil Diameter
Ray aiming      : Off
Apodization     :Uniform, factor =     0.000000
Eff. Focal Len. :     35238.7
Total Track     :     7497.78
Image Space F/# :     10.3534
Working F/#     :     10.3519
Obj. Space N.A. : 1.7018e-007
Stop Radius     :      1701.8
Parax. Ima. Hgt.:     153.759
Parax. Mag.     :           0
Entr. Pup. Dia. :      3403.6
Entr. Pup. Pos. :           0
Exit Pupil Dia. :     839.339
Exit Pupil Pos. :    -8689.72
Maximum Field   :        0.25
Primary Wave    :    0.500000
Lens Units      : Millimeters
Angular Mag.    :     4.05509

From this I'll round to $f=$ 35,200 mm, f/no. = 10.35 which gives D=3.400 meters confirmed by the stop radius of 1702 mm and entrance pupil diameter of 3404 mm, and a central occlusion of about 1120 mm diameter as estimated from this technical drawing.

Gaussian beam optics

From Wikipedia we can see how to evolve a Gaussian beam from a waist or any other point to any other point forward or backward.

However in this case it's overkill because Section 3.2.1 informs us that the $1/e^2$ diameter at 198 mm in front of the primary focus is 16mm and this is so much larger than the diameter at the spatial filter will be only a half-dozen microns or so (0.5 micron wavelength, f/10 telescope).

Thus we are in the far field and the angular shape of the beam is fixed.

If the 1/e^2 intensity (i.e. 1/e amplitude) radius $\omega$ is 8 mm at 198 mm, then it is 1422 mm at f=35,200 mm, somewhat smaller than the 1702 mm radius of the primary stop.

A diameter scan would look like this when all stops are considered:

enter image description here

and if you were looking at it with another telescope from a few kilometers away:

enter image description here

Now the far field pattern of this is going to be a little messy, and it will change a lot if focus is moved even slightly (location of the gaussian waist relative to the Nasmyth focal point). But we can integrate over the aperture assuming flat phase (in-focus) and see what happens.

It's sort-of like a narrow and a wide Airy pattern (from the primary aperture and secondary occlusion, respectively) interfering with each other, as expected.

We can see that without considering atmospheric effects the beam is a small fraction of an arcsecond wide, so the pattern that reaches the Moon will be dominated by astronomical seeing effects rather than diffraction effects until the day that adaptive optics is used to boost efficiency even further, though it seems that with all these upgrades (I haven't even mentioned the multiphoton-capable focal plane array yet) that may not be necessary.

enter image description here

import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(-2, 2, 801)
X, Y = np.meshgrid(x, x)
R = np.sqrt(X**2 + Y**2)
Z = np.exp(-(R/1.422)**2)
Z[R<0.56] = 0 # secondary occlusion
Z[R>1.702] = 0 # primary aperture
extent = [X.min(), X.max(), Y.min(), Y.max()]
plt.imshow(Z, vmin=0, vmax=1, cmap='gray', extent=extent)
plt.colorbar()
plt.show()
plt.plot(x, Z[400])
plt.ylim(0, 1)
plt.show()
thetas = 1E-06 * np.linspace(-1.9, 1.9, 201)
lam = 0.532E-06 # doubled Nd:YAG
twopi = 2 * np.pi
imgs = []
for theta in thetas:
    phase = twopi * X * theta / lam # avoid complex by symmetry (X=0 in center)
    img = np.sqrt(Z) * np.cos(phase) # sqrt for amplitude
    imgs.append(img)
arcsecs = (180/np.pi) * thetas * 3600
intensity = np.array([img.sum()**2 for img in imgs]) # sum then square for intensity
intensity /= intensity.max()
if True:
    plt.figure()
    plt.subplot(2, 1, 1)
    plt.plot(arcsecs, intensity)
    plt.subplot(2, 1, 2)
    plt.plot(arcsecs, np.log10(intensity))
    plt.ylim(-4, None)
    plt.xlabel('arcseconds')
    plt.show()
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.