16
$\begingroup$

The flame exiting the space shuttle main engine is obviously transparent. But, you can't see objects through either the Saturn V booster flame or that of the space shuttle solid rocket boosters. Is it that they are actually just as transparent as the hydrogen-fueled flame of the shuttle main engines, but emitting so brightly in visible wavelengths that transmitted light is just too dim by comparison, or is there actually material in the exhaust of a type and at sufficient density to obscure any transmitted light?

$\endgroup$
31
$\begingroup$

The reason for the transparency of the Space Shuttle Main Engine's flame is the fuel it's burning.

SSMEs burn liquid hydrogen and liquid oxygen, and when hydrogen and oxygen burn the flame is nearly invisible to the human eye. i.e. it's hardly emitting any visible light, the gases themselves are colorless, and the product of the reaction, H2O (water vapor), is also invisible.

Space Shuttle Main Engine test firing

(digression)

Another good example of this kind of “invisible” flame is the combustion of hydrazine with tetroxide, à la SpaceX SuperDraco engines (pictured).

SpaceX SuperDraco engine test firing

(/digression)

Both of your other two examples, the Saturn V first stage and the space shuttle solid boosters used much dirtier fuels.

The RP-1 that the F-1 engines on the Saturn V first stage used is a highly refined form of kerosene that burns with a very bright flame. Just like almost every engine, the F-1s didn't completely burn all their fuel before ejecting it as exhaust, add to that minute imbalances in the fuel/oxygen mix and the result is the long plume of flame that is both partially opaque from the fuel and soot from the engines, and emitting millions of Lumens of light.

Saturn V rocket ascending from the launch pad

The space shuttle solid rocket boosters burned aluminium with an oxidizer (ammonium perchlorate), along with a whole bunch of other compounds included in the propellant. What sets the solid booster exhaust apart from our other two examples is the amount of particulates it contained. It was basically chucking tons of powdered aluminium oxide (a bright white compound) into the air, thus the exhaust was completely opaque.

Space Shuttle Discovery just after lift-off

$\endgroup$
2
$\begingroup$

Flames are complicated and interesting.

They can emit light from atomic (and molecular) excited states recombining ("blue part" of flame), and, especially if there are particulates from incomplete combustion, they can glow white, yellow, or red from something similar to blackbody radiation if the incomplete combustion products agglomerate to make particulates (soot).

If the flame is in air, those can continue to combust and stay hot and glow. In a vacuum, the un-combusted material cools quickly and there is no more thermal glow. That's why the LOX/Kerosene engines make bright flames near sea level, but you don't see much of anything once they are above most of the atmosphere.

BUT: Bright is not the same as Opaque!

Transparency for a wide band of visible light (our eyes and our cameras) is not really reduced much by the atomic and molecular emission! It may be so bright that it's hard to notice the transmitted light, but that's not the same as opacity. Materials or regions of gas can be glowing AND nearly transparent at the same time!

Think about bioluminescent algae in water, or red-hot glass during glass blowing, or even Cherenkov radiation in water!

Anyway, here is a sequence of screenshots from the recent SpaceX launch of Thaicom-8 on YouTube. That's probably something between smoke and soot. LOX/Kerosene engines usually get the most thrust by running rich - more Fuel than the LOX can oxidize. That leaves a lot of carbon and hydrocarbons to absorb and scatter light. While these are not opaque - you can still see through them - they are genuinely darker due to light absorption and scattering.

enter image description here

enter image description here

enter image description here

enter image description here

enter image description here

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.