**tl;dr:**  *No chance, not even close!*

The [escape velocity](https://en.wikipedia.org/wiki/Escape_velocity) from the surface of a round (spherically symmetric) body is given by

$$v_{esc} = \sqrt{\left(\frac{2 GM}{r_0} \right)}, $$

showing that it is the $\frac{mass}{radius}$ ratio that's key here, not just the surface gravity given by 

$$a_{g} = -\frac{GM}{r_0^2}. $$

So since

$$v_{esc} = \sqrt{a_g r_0}, $$

a lower density but larger radius body with the same surface gravity would have a higher escape velocity. You can think of that as "the gravity extending outward farther" or better yet, just dropping off slower. Gravity drops by a factor of 4 at $2r_0$, so if $r_0$ is bigger, so is $2r_0$.

The problem is a little tougher because you have to look at the design of human legs. They are optimized to work in Earth gravity; they have mass an moments of inertia that work with muscle strength and the speed with which muscle fibers can contract. For that you can start with [this excellent <s>answer to</s> bibliography for](https://space.stackexchange.com/a/27250/12102) the question *Any scholarly or serious work in Sports Science for the low surface gravity of Mars or the Moon?* or other things tagged [tag:reduced-gravity-sports].

Let's look at what happens on Earth. Most people will find it a challenge to get to 1 meter in a [standing high jump](https://en.wikipedia.org/wiki/Standing_high_jump), and the world's record is 1.65 meters. Let's use 70 kg and 1 meter at $g_0$=9.8 m/s^2, some basic kinematics, and this [page](http://people.brunel.ac.uk/~spstnpl/BiomechanicsAthletics/VerticalJumping.htm) linking to the PDF [Optimum Take-Off Range in Vertical Jumping](http://people.brunel.ac.uk/~spstnpl/Publications/ANZSB2000VertJump(Linthorne)%20.pdf) to get a better picture


[![enter image description here][1]][1]

There's about a 1000 Newton force beyond the ~750 N supporting *weight against gravity*, or about 14 m/s^2, for about 0.25 meters. That's about 0.19 seconds and a take-off velocity of 2.6 m/s using $v = \sqrt{2 g h}$ and $t = \sqrt{2x/g}$.

The surface gravities of [Mimas](https://en.wikipedia.org/wiki/Mimas_(moon)) and [Ceres](https://en.wikipedia.org/wiki/Ceres_(dwarf_planet)) are 0.064 and 0.28 m/s^2 respectively, and their escape velocities are 

If you could develop only the 1000 Newtons over 0.25 meters at those surface gravities, you would also achieve that ~2.6 m/s velocity. 

However, their escape velocities are 160 and 510 m/s, respectively! So... **no chance, not even close!**

  [1]: https://i.sstatic.net/dGS7P.png