# Tag Info

A diagram showing the cross section (longitudinal section) of the earth at the same longitude as the geostationary satellite is shown below. A location from the the geo stationary satellite aligns with the horizon is marked. Its latitude is also marked in the picture. At higher latitudes, the satellite is below the horizon. $$cos(\mathrm{lat}) = \frac{6400}... 13 I think the maximum velocity change from a flyby would help quantify this.$$\Delta v \leq \sqrt{\frac{GM}{r_P}} That is, with perfect relative velocity and angle, the change in velocity from such a flyby perturbation is limited by the mass ($M$) of the asteroid, and the distance at closest encounter ($r_P$), which in the best case is to barely miss ...