# Tag Info

To see why a Hohmann transfer is applicable for a symmetric jump preserving phase angle, let's consider what the semi-major axis of the transfer ellipse is: $$a_{H} = \frac{periapsis_H + apoapsis_H}{2}$$ $$a_{H} = \frac{a - \Delta a + a + \Delta a}{2}$$ $$a_{H} = a$$ That is, the semi-major axis of the Hohmann transfer orbit is equal to the nominal orbit! ...