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$$t=\frac{\pi}{2}\frac{R^{3/2}}{\sqrt{2\mu}}$$ The formula above is for the free-fall time to a point source of gravity, with $\mu$ being the Standard gravitational parameter for the Sun. So this could be applied to the trajectory of a "released" statite. Filling in the numbers it appears that for $R$ being the radius of the orbit of Jupiter the ...


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