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Would a higher air pressure on the ISS or elsewhere make it easier to “swim” in microgravity? Yes! But what's really important is the density, so instead of pressuring "normal air" you can just make a denser atmospheric mixture and keep the pressure the same. This answer says If you want the air to be 5 times easier to swim, you can just replace ...


If you want the air to be 5 times easier to swim, you can just replace the nitrogen with xenon and increase the density without increasing pressure.


Partial answer to "Is it a proposal space agencies should consider?" Unlikely. Increasing the differential pressure by a factor of 5 would mean that the modules would have to be quite a bit stronger and therefore presumably costlier and/or heavier. (As pointed out in the other answer) If getting marooned in midair is a constant problem (AFAIK it ...


The astronauts would get nitrogen narcosis even worse than in 40 m deep water breathing air. In both cases the gas pressure is 5 bar, but under water the partial pressure of nitrogen is 3.95 bar but in the spaceship 4.79 bar. This is equivalent to about 50 m deep water breathing air. See Wikipedia for signs and symptoms of the narcosis. These symptoms would ...


It's hard to prove a negative. However, there is no documentation of usage by NASA. A search for the phrase "fountain pen" on the NASA Technical Reports Server returns 27 entries. Some of these documents are comparing something else to the size or shape of a fountain pen. Others are about using fountain pens for experiments or graphical arts on ...


A fountain pen is unlikely to be used in microgravity as it is at least partially dependent on gravity to function. The pen draws ink from the reservoir through a feed to the nib and deposits it on paper via a combination of gravity and capillary action. Source


Spaceship two has wings so in general will be producing lift and not be in true free fall. It would be possible for a winged craft to fly a negative angle of attack to achieve zero G but this will produce an ever increasing dive if starting from level flight. More likely it is a low but not zero G release with spaceship two moving away from whiteknight ...


The vehicle leaves its parent, according to Wikipedia at about $15\,\mathrm{km}$ up: well inside the atmosphere. If it doesn't light its engine it will be in free-fall, in some sense, for no time at all, at there will always be some drag from the atmosphere on it. In practice it will be for a few seconds until the atmospheric drag builds up. The expression ...


Nice observation, he is just doing it to show off! Check these out:


It could be taken at an Indoor Sky-Diving facility. These use very powerful fans to create a vertical wind-tunnel, which basically blow their customers into the air. People pay for this apparently.


The biggest give away is the size of this chamber: its too big for any of the known NASA's KC-135 or ZG's 727-200. That leaves us one other candidate: their Russian counterpart IL-76 MDK The interior, roof, lights, and door in the back ground is pretty much identical. (source:


Just a vertical movement may do, a very special case of a parabolic flight. You only need the proper acceleration to get zero gravity for a short time. A drop tower with a vacuum tube like the Fallturm Bremen will do. A drop from 110 m height delivers 4.74 seconds of weightlessness. Using a catapult from ground will double the time. For a free fall ...


The question is what minimum altitude, speed and exterior air pressure/drag must be reached in order to become weightless without having to push the yoke for lowering a spaceplane's nose. Reportedly humans start to perceive linear gravity "properly" at 0.007 g. So let's define considerable weightlessness as below 0.007 g (and above minus 0.007 g). ...

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