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21

tl;dr: No chance, not even close! The escape velocity from the surface of a round (spherically symmetric) body is given by $$v_{esc} = \sqrt{\left(\frac{2 GM}{r_0} \right)}, $$ showing that it is the $\frac{mass}{radius}$ ratio that's key here, not just the surface gravity given by $$a_{g} = -\frac{GM}{r_0^2}. $$ So since $$v_{esc} = \sqrt{a_g r_0}, $...


11

No. Fermi estimate: Mimas' gravity is 0.064 m/s2, you need gravity to be about 1/20 of that to escape using a bike and a ramp (going by Deimos' surface gravity of 1/20 that of Mimas), lower still to escape by jumping :


6

I'm going to interpret "surface" to mean Saturn's upper atmosphere. It was recently discovered that ring particles are raining down on Saturn. It’s raining on Saturn. Each second, the planet’s rings shed perhaps thousands of pounds of water ice, organic molecules, and other tiny particles into the gas giant’s clouds. This is caused by particles ...


3

Depending on your environmental suit, it would probably be much like the Apollo astronauts' mode of choice on the moon. I say "depending on your environmental suit" because the environment at Titan is very different from that on the moon. True, the gravitational acceleration is roughly the same, but a Titan environmental suit wouldn't have to protect ...


2

Here are some effective ring parameters. To simplify I'm just using the monopole term GM and not including the "extra gravity" near the planet from the oblateness which is okay since I'm rounding. (see this answer to Equation for orbital period around oblate bodies, based on J2?) ring a T ω a_z/1km Δv/day ...


1

As uhoh and Russell Borogove alluded to already, if I add a rotation rate for Saturn since Epoch J2000 for each of the moons, it matches the NASA simulation almost perfectly. Not sure why I need to do this, but it works. So when calculating the MEAN LONGITUDE for the moon, I add the following longitude rate from Saturn: MEAN LONGITUDE = MEAN LONGITUDE - (...


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