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The issue with any use of a Bussard Ramscoop is efficiency. In this answer I go into some of the propulsion details, basically in order to make it useful you have to be going a significant proportion of the speed of light to reach the break even point, where you gain more energy than you spend on maintaining the field (Note that is theoretical, we aren't ...


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Although it's an older question I just wanted to say that above answer uses the Young's modulus incorrectly. It is not supposed to be in the strength calculation. The sigma refers to a maximum strength (same units though force/area). One typical value you could use is the yield strength of the material but you could also use another value the designer is ...


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