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Jan 10, 2019 at 15:14 comment added David Schneider-Joseph Your criticism appears to be valid in the case that the proton travels straight through, as depicted in some of the diagrams. But in the reflection case I don’t believe it is.
Jan 10, 2019 at 10:21 comment added David Schneider-Joseph An analogy to a gravitational flyby may be helpful here: the spacecraft’s energy relative to the planet remains constant, but a momentum transfer still occurs because the direction of the spacecraft’s travel changes.
Jan 10, 2019 at 10:19 comment added David Schneider-Joseph Don’t you mean they must get decelerated to their original speeds (i.e. magnitude of velocity), not velocity? The direction of the particle’s velocity vector can change in the process, no? And if so, doesn’t this impart momentum?
Jul 8, 2018 at 6:13 history edited ScottBurson CC BY-SA 4.0
Added a second explanation.
Jul 6, 2018 at 20:31 history edited ScottBurson CC BY-SA 4.0
Minor clarification
Jul 6, 2018 at 18:13 review First posts
Jul 6, 2018 at 19:17
Jul 6, 2018 at 18:12 history answered ScottBurson CC BY-SA 4.0