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S Mar 6, 2014 at 12:11 history suggested Josh Jolly CC BY-SA 3.0
Correcting percentage
Mar 6, 2014 at 11:49 review Suggested edits
S Mar 6, 2014 at 12:11
Mar 6, 2014 at 3:37 comment added PearsonArtPhoto I did end up dividing the distances by 2, that wasn't made clear. Essentially, the 1/2 cancels the division by two out, I did make that clearer now though. And I thought I had typed a, not v... Sigh, not sure what mental lapse happened there... Thanks for the feedback!
Mar 6, 2014 at 3:36 history edited PearsonArtPhoto CC BY-SA 3.0
edited body
Mar 6, 2014 at 1:22 comment added Ross Millikan Usually acceleration is $a$, not $v$. You should divide the actual distances by $2$ because you accelerate for half the distance, then decelerate for the other half. This divides the times by $\sqrt 2$ The conclusion that you can get there easily and are well below the speed of light is correct.
Mar 5, 2014 at 21:13 comment added adamholtwrites I can set that scene near the midpoint when the ship moves from acceleration to deceleration. They can prepare for Europa's surface gravity at that point.
Mar 5, 2014 at 20:53 comment added PearsonArtPhoto The surface gravity of Europa is around 1.3 m/s, which isn't a high enough speed. But I suppose you could gradually go from 1g to Europa gravity, and still have time left over.
Mar 5, 2014 at 20:46 comment added adamholtwrites Thanks for the help. That works well. I may have the craft decelerate midstream to mimic the gravity of Europa, their destination. That, plus a lap or two around Jupiter for sightseeing purposes, should put me in on schedule. Am I missing anything?
Mar 5, 2014 at 20:25 history edited PearsonArtPhoto CC BY-SA 3.0
added 265 characters in body
Mar 5, 2014 at 20:13 history edited PearsonArtPhoto CC BY-SA 3.0
added 265 characters in body
Mar 5, 2014 at 20:08 history answered PearsonArtPhoto CC BY-SA 3.0