Above geosynchronous orbit, so called centrifugal force exceeds force of gravity. So earth would be above you.

Centrifugal acceleration (actually just inertia in a rotating frame) is $\omega^2r$ where ω is angular velocity in radians.

Earth's sidereal day is about 23.93 hours, so ω is about 2 pi radians/23.93 hours. or 7.3e-5 radians/second.

Acceleration from gravity is $GM_e/r^2$ where $M_e$ is mass of earth and r is distance from earth's center.

You will find that $GM_e/r^2$ and $\omega^2r$ exactly cancel at geosynchronous altitude. Above geosynchronous $\omega^2r$ exceeds $GM_e/r^2$. You will weigh more as you move further beyond geosynchronous height.

If my arithmetic is right, you wouldn't feel a full g until you're about 1.8 million kilometers from earth's center.

Above geosynchronous orbit, so called centrifugal force exceeds force of gravity. So earth would be above you.

Centrifugal acceleration (actually just inertia in a rotating frame) is $\omega^2r$ where ω is angular velocity in radians.

Earth's sidereal day is about 23.93 hours, so ω is about 2 pi radians/23.93 hours. Or 7.3e-5 radians/second.

Acceleration from gravity is $GM_e/r^2$ where $M_e$ is mass of earth and r is distance from earth's center.

You will find that $GM_e/r^2$ and $\omega^2r$ exactly cancel at geosynchronous altitude. Above geosynchronous $\omega^2r$ exceeds $GM_e/r^2$. You will weigh more as you move further beyond geosynchronous height.

If my arithmetic is right, you wouldn't feel a full g until you're about 1.8 million kilometers from earth's center.