Timeline for How can I calculate the weight a aero-spacecraft occupant experiences during sub-orbital but non-ballistic trajectories?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Apr 4, 2021 at 4:21 | vote | accept | Wesley Adams | ||
| Apr 4, 2021 at 4:20 | comment | added | Wesley Adams | Huh! I had the exact same idea for how to figure out how much gravity would need to be canceled, and I was coming back here to resolve the question. Sorry about the confusing original question by the way. I'm only just learning f = ma in class and I'm not very good with formatting my questions in an understandable way. Thanks! | |
| Apr 3, 2021 at 17:20 | comment | added | Russell Borogove | Fixed my cosine nonsense. The square relation seemed right to me at first, but then I outsmarted myself by thinking, "no, the arc of the Earth's surface is a circle, not a quadratic..." Thanks to you sensible people! | |
| Apr 3, 2021 at 17:18 | history | edited | Russell Borogove | CC BY-SA 4.0 |
added 279 characters in body
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| Apr 3, 2021 at 4:36 | comment | added | uhoh | @OrganicMarble I was focused on writing the "please feel free to yell at me" part. I'd come back a few minutes later to add the centripetal part but failed to scan for prior art. I saw "some sort of trigonometric relationship" here and under the question, got worried, and wanted to offer a simpler alternative. Now, did somebody say something about a deadline (excuses themself and leaves the room) | |
| Apr 3, 2021 at 4:29 | comment | added | Organic Marble | @uhoh I certainly thought so when I commented that 4 hours before you did. | |
| Apr 3, 2021 at 2:29 | comment | added | uhoh | I've edited the question and commented there and voted to re-open. I don't think that the edit makes any changes that affect your answer. If it does, please feel free to yell at me and/or edit it further. Also, is centripetal acceleration $v^2/r$ all that's needed here? It's non-linear, zero at zero and $g$ at orbital speed and radius. | |
| Apr 2, 2021 at 21:56 | comment | added | Russell Borogove | Yeah, that seems reasonable. | |
| Apr 2, 2021 at 21:54 | comment | added | Organic Marble | Wouldn't the upward acceleration be v^2/r? So for an SR-71 at 26 K meters (+ Earth radius) and that speed, ~.2 m/s^2 which is ~ 2% of g, pretty close to what you got. | |
| Apr 2, 2021 at 20:48 | history | answered | Russell Borogove | CC BY-SA 4.0 |