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Keplerian orbits, those around spherically symmetric mass distributions (Newton's Shell theorem collapses them to a point) have analytical solutions in that you can write $t(\theta)$ as a simple equation. Of course the reverse $\theta(t)$ can't be written and still has to be solved numerically.

But my guess is that for anything other than Keplerian orbits proper, there is no simple equation for the orbit. There are plenty of equations out there, the result of various perturbation calculations or other approximations.

For example, see

These refer to Kelperian-like orbital parameterization of orbits around an oblate/prolate spheroid characterized by $J_2$. For example the equation for nodal period including effects of eccentricity and $J_2$ was typed out in @Chris' answer:

$$T = T_0\left[1 - \frac{3J_2(4-5\sin^2 i)}{4\left(\frac{a}{R}\right)^2\sqrt{1-e^2}(1+e\cos\omega)^2} - \frac{3J_2(1-e\cos\omega)^3}{2\left(\frac{a}{R}\right)^2(1-e^2)^3}\right]$$

Here, according to the answer, $\omega$ is the argument of perigee, and $e$ and $i$ are eccentricity and inclination.

We can suspect this is might be an approximation because a real orbit around a body with nonzero $J_2$ won't have easily recognized Keplerian elements (the orbit won't even be planar!), they'd have to be redefined. But maybe in the context of this equation the non-elliptical orbit can still have a well-defined eccentricity somehow.

Question: When all is said and done, Any exact analytical solutions for non-Keplerian orbits; those around non-radially symmetric mass distributions (e.g. J₂≠0)? Or once $J_2$ deviates from zero or the central mass deviates in any way from spherically symmetric do the equations of motion always become approximations?

For the purposes of this question, "exact analytical solutions" could include infinite series, as long as they can be and have been written as such.

note: This is a complicated question to write; I'm open to comments recommending adjustments to the wording or the scope.

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  • $\begingroup$ Very good question, I have been cogitating on this too. But "orbits around an oblate/prolate spheroid characterized by $J_2$" seems to contain a misinterpretation: IMO, the $J_n$ can only model oblateness. BTW, as a first step, I would limit the scope to gravity potential involving only a $J_2$ > 0 (I don't think it can be negative). $\endgroup$
    – Ng Ph
    Commented Nov 4, 2021 at 15:39
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    $\begingroup$ can you point me to the definition of $J_{22}$ in the Wikipedia geopotential model? $\endgroup$
    – Ng Ph
    Commented Nov 4, 2021 at 20:57
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    $\begingroup$ Does this question include non-physical solutions? That is, shapes that are impossible or highly unlikely to occur in nature. I think I can come up with some examples originating in electric fields, the cousin of gravity. But you won't find any asteroids with a funny enough shape. $\endgroup$ Commented Nov 9, 2021 at 11:21
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    $\begingroup$ @SE-stopfiringthegoodguys I'm torn, because no, except you will probably come up with something really interesting so yes... :-) There's this: Could you stably orbit around a square (cubic) body? Would the orbit destabilize automatically if not corrected by input? for example $\endgroup$
    – uhoh
    Commented Nov 9, 2021 at 11:23
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    $\begingroup$ The motion of a satellite under the $J_2$ perturbation is described by a dynamical system that is not integrable, which implies that there exist no exact, closed-form analytical solutions. Source: 1, p. 5, which cites proofs 2, 3. You could still write the solution as an infinite Taylor series about the initial conditions, but I'm not sure if there might be some convergence issues. $\endgroup$
    – LeWavite
    Commented Nov 14, 2021 at 18:31

2 Answers 2

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The motion of a satellite under the 𝐽2 perturbation is described by a dynamical system that is not integrable, which means that there exist no exact, closed-form analytical solutions. Source: [1, p. 5], which cites proofs [2], [3].

You could still write the solution as an infinite Taylor series about the initial conditions, but I'm not sure if there might be some convergence issues.

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  • $\begingroup$ This is great! While not a complete answer yet, this offers helpful insight and constraints. Sounds like that if there are any solutions they are likely curiosities; special cases. $\endgroup$
    – uhoh
    Commented Nov 15, 2021 at 19:32
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    $\begingroup$ I agree. In any case, even if one could write down an analytical solution not in closed form (such as an infinite Taylor series), the computational effort for such solution would probably be higher than that of a high-accuracy, numerical solution... $\endgroup$
    – LeWavite
    Commented Nov 16, 2021 at 9:12
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    $\begingroup$ @LeWavite, nevertheless, a solution based on "brute-force" integration will not provide the insight that an infinite series may give, such as by truncating the series and analyze the closed-form approximation. $\endgroup$
    – Ng Ph
    Commented Nov 16, 2021 at 18:40
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This is to address OP's note:

This is a complicated question to write; I'm open to comments recommending adjustments to the wording or the scope.

When the force potential field of a 2-body system is perturbed, the Newtonian motion of the non-central body is no longer an ellipse around the central body. However, the motion's trajectory, limited in time, can be viewed as a distorted ellipse whose deformation varies with time. The position and velocity of the satellite at a given instant, also called the state vectors, can be used to uniquely define an ellipse, in the Keplerian sense, that would be the satellite trajectory if all perturbations were removed. This uniquely defined elliptical orbit has correspondingly Keplerian orbital elements: a, e, I, Ω, ω, and τ (semi-major axis, eccentricity, inclination, RAAN, argument of perigee, true anomaly). It is usually designated as the (Keplerian) osculating orbit, at the particular instant.

In a perturbed motion, in most practical cases (e.g. when the perturbating forces are small), the osculating elements a(t), e(t), I(t), Ω(t), ω(t), and τ(t) can be assumed to vary slowly (wrt to the "period" of any osculating orbital elements).

I will digress at this point and address one implicit question in the OP's Question: How can we define what is an "exact analytical solution"?

Let's assume that we are at the center of a circle and we observe a moving car whose path follows the circle. Assume that very far away we have a tree that we can use as a reference point.

  • The question to us is: when do we have an "exact analytical solution" for the position of the car?

We can resolve the "loose-end" of the definition of "exact analytical" by re-phrasing: Knowing that the car is in front of the tree at time T0, can you give the position of the car at any time T, so that the accuracy of your prediction is independent of how far T is from T0 and without knowledge of the positions at intermediate times?

Obviously, if the angular speed of the car is constant and known, we can close our eyes and say "give me any T, I can predict the position exactly". That is the accuracy of our prediction is dependent only on the accuracy of our knowledge of the angular speed (and the accuracy of our time keeping function, of course).

Now, this is equally true even when the car is not moving at constant angular speed. For example, it can move at one constant speed for half the circle, then at twice that speed for the 2nd half, etc.... As long as we know how the angular speed changes with time, analytically, we can predict the position without computing the intermediate positions. And this would be our definition of "exact analytical solution".

Would that mean that, mathematically speaking, the motion of our car is an integrable solution of the equation of motion? This is far beyond my mathematical reasoning capability. And furthermore, I would say it may not be of much interest in practical applications to know the answer to that theoretical question.

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