I don't know for sure, but I think it's because the panels start rolled up into a cylinder on each side, like this:
O$\square$O
If the cylinders were attached to the rectangular box in the center of opposite faces, like O-$\square$-O , then the first turn (the right-angle junction between the $-$ and the O) would be quite sharp, so it might break the panel components, and it folds in the opposite direction from the rest of the unwinding.
If instead you attach the cylinders at the corners the way DART has done, like O_$\square\bar{}\!$O , then the attachment point is already properly oriented, and the initial curvature is the gentlest possible.
The result, as Jörg said, is symmetrical: ___$\square\bar{}\!\bar{}\!\bar{}$ is symmetric under rotation, just not reflection. $-\square-$ is symmetric under both (or would be, if I could get the vertical spacing right in my $\LaTeX$ ascii art). If you mean why use ___$\square\bar{}\!\bar{}\!\bar{}$ rather than $\bar{}\!\bar{}\!\bar{}\square\bar{}\!\bar{}\!\bar{}$ (symmetric under reflection but not rotation), it's because in the way they did it, the center of mass stays near the geometric center of the spacecraft. If they attached both wings to one face, the center of mass would move toward that panel as the booms unrolled, which would make maneuver control trickier.