Estimating exact propellant consumption rate (mass flow rate) from easily available sources such as the Wikipedia page of KTDU-80 might be a bit imprecise, since we'll be using the thrust and Isp values to find mass flow rate, and in practice, it is done the other way around, as this answer by Russell Borogove suggests.
Now if rough figures are acceptable to you, we can find the mass flow rate from the definition of Specific Impulse:
$$
F_{thrust} = g_0 . I_{sp} . \dot{m}
$$
$$
\therefore \dot{m} = \frac{F_{thrust}}{g_0 . I_{sp}}
$$
Now using the values from KTDU 80's Wikipedia page,
For S5.80:
$$
\dot{m} = \frac{2950}{9.81×302} ≈ 0.9957~~kg/sec
$$
For DPO-B:
$$
\dot{m} = \frac{129.16}{9.81×291} ≈ 0.0453~~kg/sec
$$
And for DPO-M:
$$
\dot{m} = \frac{25}{9.81×285} ≈ 0.0089~~kg/sec
$$
Hope this helps! The answers to this question by uhoh discuss the applicability of the expression used above. Those might be helpful further.