How does the pattern on the MarCo cubesat's antenna boost data-transmission?

Question

I was looking at a few posts that uhoh had made about the MarCo cubesat. One of the pictures was the one that I've posted below:

Source

The most I can gather from casual NASA articles is along the lines of:

The high-gain, X-band antenna is a flat panel engineered to direct radio waves the way a parabolic dish antenna does.

While the design visually looks as if it's a parabolic-style pattern, I would like a few more specifics on the following:

• What materials are in this "pseduo-parabolic" antenna (mostly asking about the gold squares).
• How do the sizes of the squares affect the power of the antenna, I'm sure they are not arbitrary.
• How does the overall design/pattern affect the power of the dish and why?

If you have a link to any papers about the antenna that would be awesome as well, thanks.

---

Alex provided a wikipedia link which led me to find:

On board the two CubeSats is an ultra-high frequency (UHF) antenna with circular polarization. EDL information from InSight was transmitted through the UHF band at 8 kbit/s to the CubeSats, and was simultaneously retransmitted at an X band frequency at 8 kbit/s to Earth. MarCO used a deployable solar panel for power, but because of the limitations in solar panel efficiency, the power for the X-band frequency can only be about 5 watts.

So it seems the shape of the design on the antenna was designed with circular polarization in mind; what that actually means in terms of antennas though, I do not know. The wikipedia article links to this IEEE article which I do not have access to read.

Answer 1

It's the electrical equivalent of a Fresnel mirror; the reflective cousin of a Fresnel lens.

Each of the little square patterns is actually a little passive circuit that reflects the incident microwaves with a different phase shift.

It is called a Reflectarray antenna. You can read more about it in this Researchgate paper A Deployable High-Gain Antenna Bound for Mars: Developing a new folded-panel reflectarray for the first CubeSat mission to Mars.

Paywalled: The Mars Cube One deployable high gain antenna

Open Access: Reflectarray antennas: A review

The surface emulates a concave mirror, so the center needs to be the "deepest" and so the large squares delay the reflection the most. Moving out from the center the patterns delay less and less. But once you get to 360 degrees it's the same as zero, so it can go back to the longest delay.

The electrical shape emulates an off-axis parabola, optically a lot like modern satellite dish antennas.

In the mean time you can read the article in Hackaday: Interview: Nacer Chahat Designs Antennas for Mars Cubesats and you can also watch the video below.

You can also read more about MarCo hardware systems in this answer.

Source

above: Source Click for full size

The X-band antenna that transmits back to earth folds into three panels. When deployed, the reflector array is wider than it is tall so the signal source also has an array to utilize the full reflector. Interestingly, the pattern you can see on the reflector array helps the flat panels act more like a parabolic reflector. MarCO is also capable of receiving X-band from Earth using the array seen on the front face of the folded model above. These CubeSats are unable to transmit on the UHF band, they only receive the UHF communications from ground vehicles.

above: Source "MarCO Cube Sat. X-band antenna"

---

Here's another reflectarray antenna. From DARPA Prototype Reflectarray Antenna Offers High Performance in Small Package and Electron | DARPA R3D2 | Rocket Lab, though they don't show the details of the pattern required here:

Screenshot from Radio Frequency Risk Reduction Deployment Demonstration (R3D2):

---

Answer 2

Here's how to calculate the path lengths and the required phase shift to make it work. I've added a cartoon representation of squares that vary with required phase shift just to show how a real scenario might be calculated in Python.

I used the dimensions in this image in this answer and a round figure of 8.4 GHz but the sizes of the zones don't match perfectly. I'll leave it as-is rather than fudge the numbers, it's an interesting residual puzzle!

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.patches as patches

halfpi, pi, twopi = [f*np.pi for f in (0.5, 1, 2)]
degs, rads = 180/pi, pi/180

clight     = 2.9979E+08      # m/s
d, h, w,   = [0.01 * thing for thing in (31.5, 33.5, 59.7)] # meters
nx, ny     = 51, 28
nn         = 15
nnx, nny   = [nn*n for n in (nx, ny)]
dx, dy     = w/nnx, h/nny

hh, hw     = 0.5 * h, 0.5 * w
hfeed      = hh - 0.01 * 13.2
freq       = 8.4E+09         # Hz, roughly
lam        = clight/freq     # meters

theta      = rads * 22.59

X_feed     = np.array([0, hfeed, -d])

print "w, h: ", w, h
print "nx, ny: ", nx, ny
print "dx, dy: ", dx, dy

y = dy * (np.arange(nny) + 0.5)
x = dx * (np.arange(nnx) - 0.5*(nnx-1))

Y, X = np.meshgrid(y, x, indexing='ij')
Z    = np.zeros_like(X)
XYZ  = np.stack((X, Y, Z), axis=2)

r_zero   = np.sqrt(((XYZ - X_feed)**2).sum(axis=2))

OPL      = r_zero - Y * np.sin(theta)
phase    = twopi * np.mod((OPL-OPL.min())/lam, 1)

iX  = nn/2 + nn*np.arange(nx)
iY  = nn/2 + nn*np.arange(ny)
pairs = sum([[(iy, ix) for ix in iX] for iy in iY], [])
vals  = phase[zip(*pairs)]

rects = []
for pair, val in zip(pairs, vals):
    w = (nn-6) * (1-val/twopi) + 4
    y0, x0 = pair[0] - nn/2, pair[1] - nn/2
    rect = patches.Rectangle((x0,y0),w,w,linewidth=1,edgecolor=None,facecolor='k')
    rects.append(rect)

if True:
    fig = plt.figure()
    ax  = fig.add_subplot(1, 1, 1)
    wow = ax.imshow(phase, origin='lower')
    plt.colorbar(wow)
    # ax.set_title('phase')
    for rect in rects:
        ax.add_patch(rect)
    ax.set_xticklabels([])
    ax.set_yticklabels([])
    plt.show()