14
$\begingroup$

So one of the ways of calculating Isp is:

Isp = Ve/g0

You divide the effective exhaust velocity by acceleration at earth's surface. This gives you a number in seconds, and is generally considered helpful in determining an engine's efficiency.

My question is why the g0 variable? Since Isp in seconds is used for all manner of spacecraft, many of which spend years in space (probes with ion thrusters), what's the point in that g0 variable.

Would it not be more informative to simply list the effective exhaust velocity?

$\endgroup$
9
$\begingroup$

One reason for this preference is that everyone agrees on seconds as a unit for measuring time, whereas we still have multiple conventional units in use for measuring speed (m/s, ft/s).

By dividing by g0, in whatever conventional units you're used to working with (9.8 m/s2 or 32 ft/s2) you produce a value that anyone can work with, no matter which system they prefer.

$\endgroup$
  • $\begingroup$ Have you got any references? $\endgroup$ – Deer Hunter Jun 5 '15 at 6:48
  • $\begingroup$ If you don't mind a wikipedia quote: " is used both in the SI world as well as where Imperial units are used. Its chief advantages are that its units and numerical value are identical everywhere" $\endgroup$ – Damien_The_Unbeliever Jun 5 '15 at 6:52
5
$\begingroup$

Expressing specific impulse as a speed (Ve) is just as valid -- this effectively lets you use propellent mass alone vs. mass x g in the various equations.

Dividing by g0 is just a way of scaling the value and expressing specific impulse in seconds -- this effectively lets you use propellent weight in the various equations. This can be easier for some applications.

$\endgroup$
  • 1
    $\begingroup$ I think I see. For example when calculating thrust (F) by multiplying the Isp by the mass flow rate. The Isp in seconds becomes handy then, and wouldn't work unless g0 was already factored in. I think I said that right. $\endgroup$ – David Fourman Jun 4 '15 at 14:38
  • $\begingroup$ Historically, it has been easier to talk about the weight of propellent versus the mass of propellent. So putting g into these equations is pretty much standard. $\endgroup$ – Erik Jun 4 '15 at 14:44
2
$\begingroup$

Specific impulse is simply ratio of thrust to propellant consumption (mass flow) as have been mentioned. Traditionally, the force is measured by weight of unit mass (pound, kilogram). Related unit often are referred as pound force (kpf) or kilogram force (kgf). If the trust is measured by, kpf and consumption in lb/second dimension of specific impulse will be in seconds. Therefore, the answer would be g came from definition of force as weight of unit mass. In SI Isp is measured in m/sec i.e. theoretic exhaust velocity. The reason of sec to be preferred over m/sec or ft/sec is answered in previous posts.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.